Makefile按名称构建子目录(Makefile build subdirectories by name)

 我有一个golang monolith repo，里面有多个应用程序。 我在每个应用程序根目录中都有Makefile，我必须像root/app1/一样在app目录中运行make build 。 我希望在每个服务中摆脱这些相同的Makefile，并拥有一个顶级的Makefile，我可以使用它来一次构建所有应用程序，每个应用程序创建单独的可执行文件或仅构建特定的应用程序。 就像是 
 
make build app1 # builds only app1
make build # builds all apps
 
 实现这一目标的明显方法是为所有应用程序设置目标并具有构建命令，但是想知道是否有更简单的方法来做到这一点，甚至不在Makefile中为每个目标重复构建命令 

I have a golang monolith repo with multiple apps in it. I have Makefile in each app root and I have to be in the app directory like root/app1/ to run make build. I want to get rid of these identical Makefile's in each service and have a top level Makefile that I can use to build all apps at once each creating individual executables or build specific app only. Something like
 
make build app1 # builds only app1
make build # builds all apps
 
Obvious way to achieve this is to have targets for all apps and have build commands, but wanted to know if there is an easier way to do this by just not even repeating that build command per target in Makefile

原文：https://stackoverflow.com/questions/44035793