首页 \ 问答 \ 如何使用Lucene IndexReader寻找术语?(How to seek to a term using a Lucene IndexReader?)

如何使用Lucene IndexReader寻找术语?(How to seek to a term using a Lucene IndexReader?)

我试图通过部分匹配来获得多语法查询。 根据JavaDoc for MultiPhraseQuery

PhraseQuery的通用版本,可以在同一位置添加多个术语,将其视为析取(OR)。 要使用此类搜索短语“Microsoft app *”,首先创建一个Builder并在术语“microsoft”上使用MultiPhraseQuery.Builder.add(Term)(假设小写分析),然后查找所有具有“app”的术语使用LeafReader.terms(String)前缀,寻找“app”然后迭代并收集术语,直到不再有该前缀,最后使用MultiPhraseQuery.Builder.add(Term [])添加它们。 MultiPhraseQuery.Builder.build()返回完全构造(和不可变)的MultiPhraseQuery。

https://lucene.apache.org/core/6_6_0/core/org/apache/lucene/search/MultiPhraseQuery.html

我正在努力解决它所说的部分:

...使用LeafReader.terms(String)查找所有使用“app”作为前缀的术语,寻找“app”然后迭代并收集术语,直到不再有该前缀...

如何在那里寻求条款? LeafReader.terms(String)为您提供了一个Terms ,它具有iterator方法,为您提供可以使用的TermsEnum 。 我只是不确定如何使用提取匹配术语?


I'm trying to get a multi-phrased query to with a partial match. According to the JavaDoc for MultiPhraseQuery:

A generalized version of PhraseQuery, with the possibility of adding more than one term at the same position that are treated as a disjunction (OR). To use this class to search for the phrase "Microsoft app*" first create a Builder and use MultiPhraseQuery.Builder.add(Term) on the term "microsoft" (assuming lowercase analysis), then find all terms that have "app" as prefix using LeafReader.terms(String), seeking to "app" then iterating and collecting terms until there is no longer that prefix, and finally use MultiPhraseQuery.Builder.add(Term[]) to add them. MultiPhraseQuery.Builder.build() returns the fully constructed (and immutable) MultiPhraseQuery.

https://lucene.apache.org/core/6_6_0/core/org/apache/lucene/search/MultiPhraseQuery.html

I'm struggling with the part where it says:

...find all terms that have "app" as prefix using LeafReader.terms(String), seeking to "app" then iterating and collecting terms until there is no longer that prefix...

How does one seek over there terms? LeafReader.terms(String) gives you Terms which has an iterator method that gives you TermsEnum which you can seek with. I'm just not sure how extract matching terms using that?


原文:https://stackoverflow.com/questions/44703572
更新时间:2023-08-24 17:08

最满意答案

我已经注释掉了你不想要的那条线。 通过调用closePath() ,您将关闭弧的路径。

3/4弧形

JavaScript的

ctx.strokeStyle='rgb(0,250,0)';
ctx.lineWidth=10;
ctx.beginPath();
ctx.arc(100,100,45,0,Math.PI/2,true);    //use 1/4 of original angle
//ctx.closePath();
ctx.stroke();

jsFiddle


I've commented out the line you don't want. By calling closePath(), you are closing the path of your arc.

Example

3/4 Arc

JavaScript

ctx.strokeStyle='rgb(0,250,0)';
ctx.lineWidth=10;
ctx.beginPath();
ctx.arc(100,100,45,0,Math.PI/2,true);    //use 1/4 of original angle
//ctx.closePath();
ctx.stroke();

jsFiddle.

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