首页 \ 问答 \ 我们是否可以列出属于Cucumber标签的所有场景(Can we list all the scenarios which fall under a Cucumber tag)

我们是否可以列出属于Cucumber标签的所有场景(Can we list all the scenarios which fall under a Cucumber tag)

我有三四个Cucumber标签(比如@smoke,@ testing,@ test),这些标签随机放在场景和功能文件中。 现在,我需要列出所有仅在烟雾下的场景。 有人可以建议一种方法来做到这一点


I have three-four Cucumber tags (say @smoke, @testing, @test) which are randomly put on scenarios and feature files. Now, I need to list all the scenarios which fall only under smoke. Can someone please suggest a way to do this


原文:https://stackoverflow.com/questions/41716405
更新时间:2023-04-07 16:04

最满意答案

目前,两个模板都匹配相同的优先级,这被视为错误

你可以做的是首先给第一个模板一个更高的优先级

<xsl:template match="/presentation/slide" priority="2">

然后,在您的模板主体中,使用<xsl:next-match />而不是<xsl:apply-templates/>然后应用具有较低priorty的模板(请注意<xsl:apply-templates/>将会查找对于匹配子节点的模板,因此无论如何都不适合使用)。

试试这个XSLT

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                xmlns="http://www.w3.org/1999/xhtml" version="2.0">
    <xsl:output method="html"  indent="yes" />

    <xsl:template match="/presentation/slide" priority="2">
      <xsl:variable name="filename" select="concat('output_new/',@poradie,'.xhtml')"/>
      <xsl:value-of select="$filename" />
      <xsl:result-document href="{$filename}" format="xhtml">
        <html>
          <head>
            <style>
              &amp;css;
            </style>
          </head>
          <body>
            <div class="slide">
              <xsl:next-match />
            </div>
          </body>
        </html>
      </xsl:result-document>
  </xsl:template>

    <xsl:template match="slide[@type = 'title-slide']">
      <div class="container_title_slide">
        <h1><xsl:value-of select="title"/></h1>
        <h3><xsl:value-of select="autor"/></h3>
      </div>
    </xsl:template> 
</xsl:stylesheet>

(请注意,我将&css;替换为&amp;css;因为&css;不是有效的XML实体)。


At the moment, both your templates match with the same priority, which is considered an error

What you can do is firstly give the first template a higher-priority

<xsl:template match="/presentation/slide" priority="2">

Then, in your template body, use <xsl:next-match /> instead of <xsl:apply-templates/> which would then apply the template with the lower priorty (Note that <xsl:apply-templates/> would be looking for templates that match child nodes, so was not right to use in this case anyway).

Try this XSLT

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                xmlns="http://www.w3.org/1999/xhtml" version="2.0">
    <xsl:output method="html"  indent="yes" />

    <xsl:template match="/presentation/slide" priority="2">
      <xsl:variable name="filename" select="concat('output_new/',@poradie,'.xhtml')"/>
      <xsl:value-of select="$filename" />
      <xsl:result-document href="{$filename}" format="xhtml">
        <html>
          <head>
            <style>
              &amp;css;
            </style>
          </head>
          <body>
            <div class="slide">
              <xsl:next-match />
            </div>
          </body>
        </html>
      </xsl:result-document>
  </xsl:template>

    <xsl:template match="slide[@type = 'title-slide']">
      <div class="container_title_slide">
        <h1><xsl:value-of select="title"/></h1>
        <h3><xsl:value-of select="autor"/></h3>
      </div>
    </xsl:template> 
</xsl:stylesheet>

(Note that I replace &css; with &amp;css; as &css; is not a valid XML entity).

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