两点之间的直线(straight line between two points)
在HTML画布上，我有从1到N的多个点，这基本上是连接点应用程序并在touchstart上激活。
有验证，以便它们只能连接1中的点并转到2（.. n）。 问题是，现在是没有验证该线是一条直线，我正在寻找一个算法来做到这一点，这是我到目前为止所想到的
- 对于2个点（x1，y1）到（x2，y2），通过找到斜率并使用公式y = mx + b得到所有坐标
- 在touchmove上获取x，y co-ornnates并确保它是前一步中的一个点并绘制一条线，否则不绘制线。
有没有更好的方法来做到这一点，或者我可以采取任何不同的方法？
On a HTML canvas I have multiple points starting from 1 to N, this is basically a connect the dots application and is activated on touchstart.
There is validation so that they can only connect the dots from 1 and go to 2 (.. n). The issue is that right now is there is no validation that the line is a straight line and I am looking for an algorithm to do this, Here is what I have thought so far
- For 2 points (x1,y1) to (x2,y2) get all the coordinates by finding the slope and using the formula y = mx + b
- on touchmove get the x,y co-oridnates and make sure it is one of the points from the earlier step and draw a line else do not draw the line.
Is there a better way to do this or are there any different approaches that I can take ?
原文：https://stackoverflow.com/questions/5918007
更新时间：2022-12-09 10:12
最满意答案
基本上你有字典词典的字典。 对于这种情况，它简单。 但是如果你有多个这样的情况，你必须使用前两个字典的键（dict1：interface和dict2：ethernet）进行迭代
a['interfaceStatuses']['Ethernet49']['linkStatus']Basically you have dictionary of dictionary of dictionary. For this case, its simply. But if you have multiple of such cases, you have to iterate with the keys of first two dictionaries (dict1: interface and dict2: ethernet)
a['interfaceStatuses']['Ethernet49']['linkStatus']
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