将两个promise的结果输出到一个对象中(Output results of two promises into a single object)

 我有两个创建承诺的异步函数。 这两个函数都使用相同的输入i 。 
 
async function1(i) {}
async function2(i) {}
 
 我将用不同的值为我的输入多次调用这些函数，并且我希望尽可能提高代码的效率，因此我想排列承诺并使用Promise.all()并行运行它们。 
 
 然而，我想得到一个单一的结果作为我的最终输出，这将是一个像这样的对象数组： 
 
[
  {
    input: i,
    result1: result1,
    result2: result2
  },
  ...
]
 
 我通过两个独立的步骤完成了这个工作： 
 
 
 
 
 
  
async function function1(i) {
  return i * i
}

async function function2(i) {
  return i * i * i
}

async function main() {
  var promises = []

  for (let i = 0; i < 10; i++) {
    let promise = function1(i)
      .then(function(result1) {
          return {i:i, result1:result1}
      });

    promises.push(promise)
  }

  var final = await Promise.all(promises)
  
  var promises2 = [];
  
  for (let i = 0; i < 10; i++) {
    let promise = function2(i)
    .then (function(result2) {
      final[i]['result2'] = result2;
    });
    
    promises2.push(promise);
  }
  
  await Promise.all(promises2)
  
  console.log(final)

}

main()
 
 
 
 
 
 不过，我觉得这可以通过一个Promise.all() 。 你能告诉我如何？ 

I have two asynchronous functions which create promises. Both functions use the same input i.
 
async function1(i) {}
async function2(i) {}
 
I will be calling these functions multiple times with different values for my input, and I want to make my code as efficient as possible, so I want to queue the promises and have them run in parallel using Promise.all().
 
However, I want to get a single result as my final output, which will be an array of objects like so:
 
[
  {
    input: i,
    result1: result1,
    result2: result2
  },
  ...
]
 
I have accomplished this in two descrete steps:
 
 
 
 
 
  
async function function1(i) {
  return i * i
}

async function function2(i) {
  return i * i * i
}

async function main() {
  var promises = []

  for (let i = 0; i < 10; i++) {
    let promise = function1(i)
      .then(function(result1) {
          return {i:i, result1:result1}
      });

    promises.push(promise)
  }

  var final = await Promise.all(promises)
  
  var promises2 = [];
  
  for (let i = 0; i < 10; i++) {
    let promise = function2(i)
    .then (function(result2) {
      final[i]['result2'] = result2;
    });
    
    promises2.push(promise);
  }
  
  await Promise.all(promises2)
  
  console.log(final)

}

main()
 
 
 
 
 
However, I feel like this can be accomplished using a single Promise.all(). Can you tell me how?

原文：https://stackoverflow.com/questions/50498186