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Laravel4：我如何使用Eloquent / Model(Laravel4: How can I use Eloquent/Model)

 我已经阅读并阅读了http://laravel.com/docs/eloquent上的文档，我尝试了一些我在这里找到的代码，这是我到目前为止的代码模型  
 dbeloquent.php  
<?php
class dbeloquent extends Eloquent {

   protected  $table = "users";


    public  function showTbl()
        {
             dd(dbeloquent::$table);
        }
}

//end of model
?>

    route.php

<?php
Route::get('/', function () {
    $model = new dbeloquent();   
    dd($model->someFunction());
});
?>
 
 我想首先展示我的桌子，但这就是我所拥有的  
 
  访问未声明的静态属性：dbeloquent :: $ table  
 
 请有人帮帮我 

I've read and followed documentation found here http://laravel.com/docs/eloquent and I tried some of the examples i found here here is the code that I have so far model  
dbeloquent.php 
<?php
class dbeloquent extends Eloquent {

   protected  $table = "users";


    public  function showTbl()
        {
             dd(dbeloquent::$table);
        }
}

//end of model
?>

    route.php

<?php
Route::get('/', function () {
    $model = new dbeloquent();   
    dd($model->someFunction());
});
?>
 
I want to show my tables first but here is what I'm having 
 
 Access to undeclared static property: dbeloquent::$table 
 
somebody help me please

原文：https://stackoverflow.com/questions/22006637

更新时间：2022-05-06 19:05

最满意答案

 总是有很多方法可以做到，因此要将文件上传到S3存储桶中，您可以：  
 
  使用aws CLI并运行aws s3 cp ...  
  使用aws CLI并运行aws s3api put-object ...  
  使用aws SDK（您选择的语言）  
 
 您也可以使用sync方法，但对于单个文件，则不需要同步整个目录，并且通常在寻找更好的性能时，最好启动多个cp实例以受益于多线程vs同步单线程。  
 基本上所有这些方法都是aws S3 API调用的封装。 从亚马逊文件  
 
  直接从代码中调用REST API调用可能很麻烦。 它要求您编写必要的代码来计算有效签名以验证您的请求。 我们推荐以下替代方案：  
  
   使用AWS软件开发工具包发送您的请求（请参阅示例代码和库）。 使用此选项，您不需要编写代码来计算请求身份验证的签名，因为SDK客户端使用您提供的访问密钥来验证您的请求。 除非您有充分的理由不这样做，否则应始终使用AWS软件开发工具包 。  
   使用AWS CLI创建Amazon S3 API调用。 有关设置AWS CLI和示例Amazon S3命令的信息，请参阅以下主题：在Amazon Simple Storage Service开发人员指南中设置AWS CLI。 在AWS Command Line Interface用户指南中使用Amazon S3和AWS Command Line Interface。  
  
 
 所以亚马逊会推荐使用SDK。 在一天结束时，我认为它确实是你最舒服的一件事，以及你将如何将这段代码整合到你的程序的其余部分。 对于一次性行动，我总是去CLI。  
 就性能而言，使用其中一个或另一个不会再起作用，它们只是对AWS API调用的封装。 对于传输优化，您应该查看aws s3传输加速并查看是否可以启用它 

There's always more than way to make on thing, so to upload a file into a S3 bucket you can : 
 
 use aws CLI and run aws s3 cp ... 
 use aws CLI and run aws s3api put-object ... 
 use aws SDK (your language of choice) 
 
you can also use sync method but for a single file, there's no need to sync a whole directory, and generally when looking for better performance its better to start multiple cp instances to benefit from multi thread vs sync mono-thread. 
basically all this methods are wrapper for the aws S3 API calls. From amazon doc 
 
 Making REST API calls directly from your code can be cumbersome. It requires you to write the necessary code to calculate a valid signature to authenticate your requests. We recommend the following alternatives instead: 
  
  Use the AWS SDKs to send your requests (see Sample Code and Libraries). With this option, you don't need to write code to calculate a signature for request authentication because the SDK clients authenticate your requests by using access keys that you provide. Unless you have a good reason not to, you should always use the AWS SDKs. 
  Use the AWS CLI to make Amazon S3 API calls. For information about setting up the AWS CLI and example Amazon S3 commands see the following topics: Set Up the AWS CLI in the Amazon Simple Storage Service Developer Guide. Using Amazon S3 with the AWS Command Line Interface in the AWS Command Line Interface User Guide. 
  
 
so Amazon would recommend to use the SDK. At the end of the day, I think its really a matter to what you're most comfortable and how you will integrate this piece of code into the rest of your program. For one-time action, I always go to CLI. 
In term of performance though, using one or the other will not make difference as again they're just wrapper to AWS API call. For transfer optimization, you should look at aws s3 transfer acceleration and see if you can enable it

Laravel4：我如何使用Eloquent / Model(Laravel4: How can I use Eloquent/Model)

最满意答案

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