计算数组中对象中两个键的出现次数(count occurrences of two keys in objects in array)

 我有以下数组与对象，并使用以下代码创建一个键“id”的计数器： 
 
 
 
 
 
  
var arr=[
{ id: 123, 
  title: "name1",
  status: "FAILED"
},
{
 id: 123,
 title: "name1", 
 status: "PASSED"
},
{
 id: 123,
 title: "name1",
 status: "PASSED"
},
{
 id: 123,
 title: "name1",
 status: "PASSED"
},
{
 id: 1234,
 title: "name2",
 status: "FAILED"
},
{
 id: 1234,
 title: "name2",
 status: "PASSED"
}

];


const test =arr.reduce((tally, item) => {
				
			  if (!tally[item.id]) {
				tally[item.id] = 1;
			  } else {
				tally[item.id] = tally[item.id] + 1;
			  }
			  return tally;
			}, {});
      
console.log(test);
 
 
 
 
 
 现在我想要做的是修改计数以考虑关键状态，所以结果将是这样的： 
 
[
{id:123, status:"PASSED", tally:3},
{id:123, status:"FAILED", tally:1},
{id:1234, status:"PASSED", tally:1},
{id:1234, status:"FAILED", tally:1}
]
 
 任何想法？ 谢谢！ 

I have the following array with objects and used the following code to creating a tally with the key "id":
 
 
 
 
 
  
var arr=[
{ id: 123, 
  title: "name1",
  status: "FAILED"
},
{
 id: 123,
 title: "name1", 
 status: "PASSED"
},
{
 id: 123,
 title: "name1",
 status: "PASSED"
},
{
 id: 123,
 title: "name1",
 status: "PASSED"
},
{
 id: 1234,
 title: "name2",
 status: "FAILED"
},
{
 id: 1234,
 title: "name2",
 status: "PASSED"
}

];


const test =arr.reduce((tally, item) => {
				
			  if (!tally[item.id]) {
				tally[item.id] = 1;
			  } else {
				tally[item.id] = tally[item.id] + 1;
			  }
			  return tally;
			}, {});
      
console.log(test);
 
 
 
 
 
Now what I want to do is to modify the tally to take in consideration the key status as well so the result will be somthing like:
 
[
{id:123, status:"PASSED", tally:3},
{id:123, status:"FAILED", tally:1},
{id:1234, status:"PASSED", tally:1},
{id:1234, status:"FAILED", tally:1}
]
 
Any idea? Thanks!

原文：https://stackoverflow.com/questions/51153174