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jsp中的分页(pagination in jsp)

我有一个超过3000行结果集的查询。 我使用迭代器来迭代每条记录。 所以我必须减少系统的负载,我想最好的方法是在jsp中使用分页。 如果有人有更好的主意,我会很高兴听到它。 类似于获取数字或类似的东西。 演示技术是struts。 如果您认为分页很好,请帮助我。


I have a query with more than 3000 rows result set. I used an iterator to iterate each record. So I have to reduce the load of system and I suppose the best way is using the pagination in jsp. If anyone has a better idea I would be glad to hear it. something like fetch number or something like this. The presentation technology is struts. If you think pagination is good please help me.


原文:https://stackoverflow.com/questions/13134912
更新时间:2022-05-14 13:05

最满意答案

创建一个可调整大小的集合,然后检查每个元素是否出现在第二个列表中(如果没有则添加它):

# items can be added to a collection
# this method creates an empty array and pass it to a collection
$missingSoftware = {""}.Invoke() 


Foreach($name in $softwareList){
# if doesnt appear
if (-not($softwareToBeInstalled.name.Contains($name))){
        # add it to the collection
        $missingSoftware.add($name)
    }
}

write $missingSoftware

Create a collection which is resizeable, then check for each element if its appears on the 2nd list ( and add it if not ):

# items can be added to a collection
# this method creates an empty array and pass it to a collection
$missingSoftware = {""}.Invoke() 


Foreach($name in $softwareList){
# if doesnt appear
if (-not($softwareToBeInstalled.name.Contains($name))){
        # add it to the collection
        $missingSoftware.add($name)
    }
}

write $missingSoftware

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