首页 \ 问答 \ 在json树中查找值并返回路径(Find value in json tree and return the path)

在json树中查找值并返回路径(Find value in json tree and return the path)

我有孩子的数据,我必须按名称找到元素并打印元素的路径。 我写了搜索功能,找到了元素,但无法处理PATH。 我应该在哪里处理它? 如何在搜索时添加或删除路径?

 let data = {
type: "folder",
name: "animals",
children: [
    {
        type: "folder",
        name: "cat",
        children: [
            {
                type: "folder",
                name: "images",
                children: [
                    {
                        type: "file",
                        name: "cat001.jpg"
                    }, {
                        type: "file",
                        name: "cat002.jpg"
                    }
                ]
            },
            {
                type: "folder",
                name: "images",
                children: [
                    {
                        type: "file",
                        name: "cat001.jpg"
                    }, {
                        type: "file",
                        name: "cat002.jpg"
                    }
                ]
            }
        ]
    },
    {
        type: "folder",
        name: "dog",
        children: [
            {
                type: "folder",
                name: "images",
                children: [
                    {
                        type: "file",
                        name: "dog001.jpg"
                    }, {
                        type: "file",
                        name: "dog002.jpg"
                    }
                ]
            }
        ]
    },
    {
        type: "file",
        name: "horse.png"
    },
    {
        type: "file",
        name: "bear.png"
    },
    {
        type: "file",
        name: "horse.png"
    }
]

};

search(data, name, path = "") {
    if (data.name == name) {
        let path = [data.name];
        return path;
    } else if (data.children != null) {
        let result = null;
        for (let i = 0; result == null && i < data.children.length; i++) {
            result = this.search(data.children[i], name);
        }
        return result;
    }
    return null;
}

I have data with children, i have to find element by name and print the path to element. I wrote search fucntion that finds the element, but can't handle with PATH. Where i should handle it? How to add or remove path while searching?

 let data = {
type: "folder",
name: "animals",
children: [
    {
        type: "folder",
        name: "cat",
        children: [
            {
                type: "folder",
                name: "images",
                children: [
                    {
                        type: "file",
                        name: "cat001.jpg"
                    }, {
                        type: "file",
                        name: "cat002.jpg"
                    }
                ]
            },
            {
                type: "folder",
                name: "images",
                children: [
                    {
                        type: "file",
                        name: "cat001.jpg"
                    }, {
                        type: "file",
                        name: "cat002.jpg"
                    }
                ]
            }
        ]
    },
    {
        type: "folder",
        name: "dog",
        children: [
            {
                type: "folder",
                name: "images",
                children: [
                    {
                        type: "file",
                        name: "dog001.jpg"
                    }, {
                        type: "file",
                        name: "dog002.jpg"
                    }
                ]
            }
        ]
    },
    {
        type: "file",
        name: "horse.png"
    },
    {
        type: "file",
        name: "bear.png"
    },
    {
        type: "file",
        name: "horse.png"
    }
]

};

search(data, name, path = "") {
    if (data.name == name) {
        let path = [data.name];
        return path;
    } else if (data.children != null) {
        let result = null;
        for (let i = 0; result == null && i < data.children.length; i++) {
            result = this.search(data.children[i], name);
        }
        return result;
    }
    return null;
}

原文:https://stackoverflow.com/questions/37460822
更新时间:2022-07-01 17:07

最满意答案

没有索引是疯狂的。

这将有所帮助,但索引键长度只能是900字节。

但是,很可能您已经有重复项目,因为第二个EXISTS可能会在第一个EXISTS之后但第一个INSERT之前运行。

索引创建会告诉你,并随后防止这种情况发生。

但是,您可以在重负载下获得错误。

我喜欢的高插入/低重复的方法是JFDI模式。 高度并发

BEGIN TRY
   INSERT etc
END TRY
BEGIN CATCH
    IF ERROR_NUMBER() <> 2627
      RAISERROR etc
END CATCH

It's madness not to have an index.

It would help but the index key length can only be 900 bytes.

However, it's likely you already have duplicates because the potential for a 2nd EXISTS to run after the 1st EXISTS but before the 1st INSERT.

The index creation will tell you, and subsequently protect against this.

However, you can get errors under heavy load.

My favoured approach for high inserts/low duplicates is the JFDI pattern. Highly concurrent

BEGIN TRY
   INSERT etc
END TRY
BEGIN CATCH
    IF ERROR_NUMBER() <> 2627
      RAISERROR etc
END CATCH

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