首页 \ 问答 \ json对象发布到Android应用程序中的PHP脚本(json object post to php script in android app)

json对象发布到Android应用程序中的PHP脚本(json object post to php script in android app)

我试过这个android代码发送json对象到我的网站

HttpPost httppost = new HttpPost(url);

JSONObject j = new JSONObject();
    j.put("name","name ");

        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
        String format = s.format(new Date()); 
    nameValuePairs.add(new BasicNameValuePair("msg",j.toString() ));

       httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
                               httpclient.execute(httppost);

而这个PHP代码

<?php

$msg=$_POST["msg"]; 

$filename="androidmessages.html";

file_put_contents($filename,$msg."<br />",FILE_APPEND);

$androidmessages=file_get_contents($filename);

echo $androidmessages;
?>

它会告诉我{“name”:“name”}但如果我使用的话

httppost.setHeader( "Content-Type", "application/json" );

它没有显示任何内容。我之前没有关于json对象帖子的经验,但我认为出了问题。我想将一些用户信息发送到我的网站并在网页上显示它可以告诉我我需要改变什么才能克服这个问题问题谢谢


I tried this android code for send json objects to my website

HttpPost httppost = new HttpPost(url);

JSONObject j = new JSONObject();
    j.put("name","name ");

        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
        String format = s.format(new Date()); 
    nameValuePairs.add(new BasicNameValuePair("msg",j.toString() ));

       httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
                               httpclient.execute(httppost);

And this php code

<?php

$msg=$_POST["msg"]; 

$filename="androidmessages.html";

file_put_contents($filename,$msg."<br />",FILE_APPEND);

$androidmessages=file_get_contents($filename);

echo $androidmessages;
?>

It will show me {"name":"name "} but if i use

httppost.setHeader( "Content-Type", "application/json" );

it will show nothing.I have no before experince about json object post but i think something went wrong.I want to send some user information to my website and display it in web page can you please tell me what i need to change to overcome this problem Thank you


原文:https://stackoverflow.com/questions/17896232
更新时间:2022-02-27 18:02

最满意答案

凯文解释了问题所在,并且你的假设是正确的。 对于这样的功能类,你可以应用一个简单的修复:

time_t now;
struct tm local_time;

now = time(NULL);
local_time = *localtime(&now);

localtime(&now)返回时,静态分配的结构的内容将被复制到本地结构local_time

编辑:还有很多其他的事情要说:

  1. 使用线程之间的函数仍然有问题...
  2. 在许多实现中,在mktimegmtime之间共享相同的缓冲区,所以也可以使用这些缓冲区来修改结构。
  3. C99和C11提供更安全的功能[TR 24731-1]。

    localtime_s(const time_t * restrict timer, struct tm * restrict dst);


Kevin explained what the problem is, and that your assumption is correct. For such classes of functions you could apply a simple fixing:

time_t now;
struct tm local_time;

now = time(NULL);
local_time = *localtime(&now);

On return from localtime(&now) the contents of the statically allocated structure will be copied on the local structure local_time.

EDIT: There are many other things to say:

  1. You still have a problem using the function between threads...
  2. The same buffer is shared, on many implementations, between mktime and gmtime, so also using these can modify the structure.
  3. C99 & C11 offer a safer function [TR 24731-1].

    localtime_s(const time_t * restrict timer, struct tm * restrict dst);

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