首页 \ 问答 \ jquery JSON没有从jQ AJAX请求解析(jquery JSON not parsing from jQ AJAX request)

jquery JSON没有从jQ AJAX请求解析(jquery JSON not parsing from jQ AJAX request)

我对jQuery相当陌生,我的JSON数据似乎没有解析我期望的方式。

所以我用json_encode($ var)创建了我的数据; 在PHP中,这似乎工作正常:

{"id":"7","0":"7","ip":"86.152.117.159","1":"86.152.117.159","proxyip":"86.152.117.159","2":"86.152.117.159","ping":"1","3":"1","time":"03:39:17","4":"03:39:17"}{"id":"6","0":"6","ip":"86.152.117.159","1":"86.152.117.159","proxyip":"86.152.117.159","2":"86.152.117.159","ping":"1","3":"1","time":"03:36:20","4":"03:36:20"}

(这是通过jQuery的AJAX从同一服务器/域上的单独URL导入的)。

但是,当我使用此代码尝试导入它时:

$.ajax({url:"load.php",success:function(result){
            var obj = jQuery.parseJSON(result);
            $(".response").html(obj.id);
        }});

并检查我的控制台,我得到“Uncaught SyntaxError:Unexpected token {”,它指向index.php中的“第1行” - 注意我没有使用外部JS文件。

我不知道我做错了什么以及如何解决这个问题所以我可以在页面上以非json形式显示数据(即在表格中)

任何帮助是极大的赞赏!

编辑:

这是我的load.php文件:

try {
    $db = new PDO("mysql:host=$mysql_host;dbname=$mysql_db", $mysql_user, $mysql_pass);
} catch(PDOException $e) {
    $e->getMessage();
}

$update = "SELECT * FROM traffic";
foreach ($db->query($update) as $user) {
    echo json_encode($user);
}

I'm fairly new to jQuery and my JSON data doesn't seem to be parsing the way i expect it to be.

So i've created my data by json_encode($var); in PHP and that seems to work fine:

{"id":"7","0":"7","ip":"86.152.117.159","1":"86.152.117.159","proxyip":"86.152.117.159","2":"86.152.117.159","ping":"1","3":"1","time":"03:39:17","4":"03:39:17"}{"id":"6","0":"6","ip":"86.152.117.159","1":"86.152.117.159","proxyip":"86.152.117.159","2":"86.152.117.159","ping":"1","3":"1","time":"03:36:20","4":"03:36:20"}

(This is being imported via jQuery's AJAX from a separate URL on the same-server/domain).

But when i use this code to try to import it:

$.ajax({url:"load.php",success:function(result){
            var obj = jQuery.parseJSON(result);
            $(".response").html(obj.id);
        }});

and check my console, i get "Uncaught SyntaxError: Unexpected token {" which points to "line 1" in index.php - Note i'm not using an external JS file.

I don't know what i'm doing wrong and how i should go about fixing the issue so i can display the data in a non-json form on the page (i.e in a table)

Any help is greatly appreciated!

Edit:

Here's my load.php file:

try {
    $db = new PDO("mysql:host=$mysql_host;dbname=$mysql_db", $mysql_user, $mysql_pass);
} catch(PDOException $e) {
    $e->getMessage();
}

$update = "SELECT * FROM traffic";
foreach ($db->query($update) as $user) {
    echo json_encode($user);
}

原文:https://stackoverflow.com/questions/27660889
更新时间:2022-01-17 08:01

最满意答案

如果找到的部分始终是第二部分并且以“ - ”分隔,那么您可以使用以下公式:

=INDEX(F:F,MATCH(MID(A2,FIND("-",A2)+1,FIND("-",SUBSTITUTE(A2,MID(A2,FIND("-",A2)+1,999),""))-1),E:E,0))

在此处输入图像描述


如果没有,那么您将需要使用此数组公式:

=INDEX($F$2:$F$3,MATCH(TRUE,ISNUMBER(SEARCH($E$2:$E$3,A2)),0))

作为数组公式,需要在退出编辑模式时使用Ctrl-Shift-Enter而不是Enter来确认。 如果正确完成,Excel会在公式周围放置{}

在此处输入图像描述


If the part that is being found is always the second part and deliniated with "-" then you can use this formula:

=INDEX(F:F,MATCH(MID(A2,FIND("-",A2)+1,FIND("-",SUBSTITUTE(A2,MID(A2,FIND("-",A2)+1,999),""))-1),E:E,0))

enter image description here


If not then you will need to use this array formula:

=INDEX($F$2:$F$3,MATCH(TRUE,ISNUMBER(SEARCH($E$2:$E$3,A2)),0))

Being an array formula it needs to be confirmed with Ctrl-Shift-Enter instead of Enter when exiting edit mode. If done correctly Excel will put {} around the formula.

enter image description here

相关问答

更多

相关文章

更多

最新问答

更多
  • 您如何使用git diff文件,并将其应用于同一存储库的副本的本地分支?(How do you take a git diff file, and apply it to a local branch that is a copy of the same repository?)
  • 将长浮点值剪切为2个小数点并复制到字符数组(Cut Long Float Value to 2 decimal points and copy to Character Array)
  • OctoberCMS侧边栏不呈现(OctoberCMS Sidebar not rendering)
  • 页面加载后对象是否有资格进行垃圾回收?(Are objects eligible for garbage collection after the page loads?)
  • codeigniter中的语言不能按预期工作(language in codeigniter doesn' t work as expected)
  • 在计算机拍照在哪里进入
  • 使用cin.get()从c ++中的输入流中丢弃不需要的字符(Using cin.get() to discard unwanted characters from the input stream in c++)
  • No for循环将在for循环中运行。(No for loop will run inside for loop. Testing for primes)
  • 单页应用程序:页面重新加载(Single Page Application: page reload)
  • 在循环中选择具有相似模式的列名称(Selecting Column Name With Similar Pattern in a Loop)
  • System.StackOverflow错误(System.StackOverflow error)
  • KnockoutJS未在嵌套模板上应用beforeRemove和afterAdd(KnockoutJS not applying beforeRemove and afterAdd on nested templates)
  • 散列包括方法和/或嵌套属性(Hash include methods and/or nested attributes)
  • android - 如何避免使用Samsung RFS文件系统延迟/冻结?(android - how to avoid lag/freezes with Samsung RFS filesystem?)
  • TensorFlow:基于索引列表创建新张量(TensorFlow: Create a new tensor based on list of indices)
  • 企业安全培训的各项内容
  • 错误:RPC失败;(error: RPC failed; curl transfer closed with outstanding read data remaining)
  • C#类名中允许哪些字符?(What characters are allowed in C# class name?)
  • NumPy:将int64值存储在np.array中并使用dtype float64并将其转换回整数是否安全?(NumPy: Is it safe to store an int64 value in an np.array with dtype float64 and later convert it back to integer?)
  • 注销后如何隐藏导航portlet?(How to hide navigation portlet after logout?)
  • 将多个行和可变行移动到列(moving multiple and variable rows to columns)
  • 提交表单时忽略基础href,而不使用Javascript(ignore base href when submitting form, without using Javascript)
  • 对setOnInfoWindowClickListener的意图(Intent on setOnInfoWindowClickListener)
  • Angular $资源不会改变方法(Angular $resource doesn't change method)
  • 在Angular 5中不是一个函数(is not a function in Angular 5)
  • 如何配置Composite C1以将.m和桌面作为同一站点提供服务(How to configure Composite C1 to serve .m and desktop as the same site)
  • 不适用:悬停在悬停时:在元素之前[复制](Don't apply :hover when hovering on :before element [duplicate])
  • 常见的python rpc和cli接口(Common python rpc and cli interface)
  • Mysql DB单个字段匹配多个其他字段(Mysql DB single field matching to multiple other fields)
  • 产品页面上的Magento Up出售对齐问题(Magento Up sell alignment issue on the products page)