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静态WCF代理类对象(static WCF proxy class object)

  1. 我在NetTCP Binding上有一个WCF应用程序。 在客户端应用程序中,我已将其代理类对象创建为静态。 此客户端应用程序可能会在部署后运行4-8小时。 基本上在登录窗口我创建并初始化DataServiceClient代理类(主要是数据库插入和更新)并在我的应用程序中使用相同的对象,直到用户关闭主窗口。 创建代理类的静态对象是否有任何不利影响(性能明智)? 如果是,那我怎么能避免这种情况。 在使用静态对象之前,我在每个窗口(在需要的地方)创建单个对象,但这增加了窗口加载时间。

  2. 如何提高WCF性能。 我对它的表现感到满意,但这可能是我的错觉。


  1. I have a WCF app on NetTCP Binding based. In client app i have created its proxy class object as static. This client app may run for 4-8 hrs after deployment. Basically at login window I am creating and initializing DataServiceClient proxy class (mainly database insert & updates) and using same object throughout my application until user closes Main Window. Is there any adverse effect (performance wise) of creating static object of proxy class? If yes then how I can avoid this. Before using static object I was creating individual object at every window (wherever required) but this had increased window loading time.

  2. How I can improve WCF performance. I am satisfied with its performance but it could be my illusion.


原文:https://stackoverflow.com/questions/3460332
更新时间:2023-11-26 13:11

最满意答案

您可以使用立交桥涡轮增压器完成此任务:以下解决方案将识别与国家公园关系边界相交的所有方式。

尝试在立交桥涡轮增压! http://overpass-turbo.eu/s/aSN

只需导航到您感兴趣的区域,然后点击“运行”。

以下是此查询如何工作的简要说明:

// restrict search to current bounding box
[bbox:{{bbox}}];          
// get all relations with tag boundary = national_park             
rel[boundary=national_park];           
// get all ways in this relation and store it in inputset boundaryways
way(r)->.boundaryways;
// now get all highway ways, which intersect our ways in boundaryways 
way[highway](around.boundaryways:0);
// exclude ways with tag highway=* which are part of the boundary relation
(._; - way.boundaryways[highway];);
// print result
out geom;

You could use overpass turbo for this task: the following solution will identify all ways, which intersect with the boundary of a national park relation.

Try it in overpass turbo! http://overpass-turbo.eu/s/aSN

Just navigate to the area you're interested in and hit "Run".

Here's a brief explanation how this query works:

// restrict search to current bounding box
[bbox:{{bbox}}];          
// get all relations with tag boundary = national_park             
rel[boundary=national_park];           
// get all ways in this relation and store it in inputset boundaryways
way(r)->.boundaryways;
// now get all highway ways, which intersect our ways in boundaryways 
way[highway](around.boundaryways:0);
// exclude ways with tag highway=* which are part of the boundary relation
(._; - way.boundaryways[highway];);
// print result
out geom;

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