首页 \ 问答 \ 如何检查多少行以数字开头(How to check how many line start with digit)

如何检查多少行以数字开头(How to check how many line start with digit)

假设一个字符串“ text ”代表多行,我怎么才能算出一个数字开头的行数?

def digit_leading_lines(text):
    n = 0
    newlist = text.split()
    for i in range (len(newlist)):
        for j in range (len(newlist[i])):
            if newlist[i][j].isdigit() == True:
                n += 1
    return n 

一旦我用text =' AAA\n1st '测试它,它会给出正确的输出为1.但是当我输入text =“ \t4G\nHz\n ”时,它会导致第一行以tab开头,输出应该是0但是,它仍然给我1作为输出。

而当我测试“ 0\n0 3\n\n ”时,它给了我错误的输出3.感谢您的帮助。


Assume a string 'text' represents multiple lines, how do I count that how many lines starts with a digit?

def digit_leading_lines(text):
    n = 0
    newlist = text.split()
    for i in range (len(newlist)):
        for j in range (len(newlist[i])):
            if newlist[i][j].isdigit() == True:
                n += 1
    return n 

Once I test it with text = 'AAA\n1st', it gives the right output as 1. But when I input text = "\t4G\nHz\n", which cause the first line start with tab, and output should be 0. However, it still gives me 1 as output.

And when I test for "0\n0 3\n\n" it gives me wrong output 3. Thanks for any help.


原文:https://stackoverflow.com/questions/36114324
更新时间:2020-01-18 19:24

最满意答案

Collections框架有更多好处 - 除非你真的需要使用它们,否则通常应该避免使用它们。 不过,既然您已经要求使用数组,那么您可以使用Collections为您完成繁重的工作。

要创建两个大小相同的团队,请从组中随机选择团队成员:

Player[] online = getServer().getOnlinePlayers(); // don't need to code "this."
List<Player> list = Arrays.asList(online);
Collections.shuffle(list);
Player[] team1 = list.subList(0, list.size() / 2).toArray(online);
Player[] team2 = list.subList(list.size() / 2, list.size()).toArray(online);

此代码可满足该组中奇数个玩家的需求。

如果你正在使用集合(一个集合将是正确的集合使用)而不是数组,那么任务就会简单得多。


The Collections framework has more goodies - you should in general avoid arrays unless you really need to use them. Nevertheless, since you have asked for arrays, here's how you can use Collections to do the heavy lifting for you.

To create two teams of equal size, selecting team members randomly from a group:

Player[] online = getServer().getOnlinePlayers(); // don't need to code "this."
List<Player> list = Arrays.asList(online);
Collections.shuffle(list);
Player[] team1 = list.subList(0, list.size() / 2).toArray(online);
Player[] team2 = list.subList(list.size() / 2, list.size()).toArray(online);

This code cater for an odd number of players in the group.

If you were working with Collections (a Set would be the right Collection to use) and not arrays, the task would be far simpler.

相关问答

更多

相关文章

更多

最新问答

更多
  • 您如何使用git diff文件,并将其应用于同一存储库的副本的本地分支?(How do you take a git diff file, and apply it to a local branch that is a copy of the same repository?)
  • 将长浮点值剪切为2个小数点并复制到字符数组(Cut Long Float Value to 2 decimal points and copy to Character Array)
  • OctoberCMS侧边栏不呈现(OctoberCMS Sidebar not rendering)
  • 页面加载后对象是否有资格进行垃圾回收?(Are objects eligible for garbage collection after the page loads?)
  • codeigniter中的语言不能按预期工作(language in codeigniter doesn' t work as expected)
  • 在计算机拍照在哪里进入
  • 使用cin.get()从c ++中的输入流中丢弃不需要的字符(Using cin.get() to discard unwanted characters from the input stream in c++)
  • No for循环将在for循环中运行。(No for loop will run inside for loop. Testing for primes)
  • 单页应用程序:页面重新加载(Single Page Application: page reload)
  • 在循环中选择具有相似模式的列名称(Selecting Column Name With Similar Pattern in a Loop)
  • System.StackOverflow错误(System.StackOverflow error)
  • KnockoutJS未在嵌套模板上应用beforeRemove和afterAdd(KnockoutJS not applying beforeRemove and afterAdd on nested templates)
  • 散列包括方法和/或嵌套属性(Hash include methods and/or nested attributes)
  • android - 如何避免使用Samsung RFS文件系统延迟/冻结?(android - how to avoid lag/freezes with Samsung RFS filesystem?)
  • TensorFlow:基于索引列表创建新张量(TensorFlow: Create a new tensor based on list of indices)
  • 企业安全培训的各项内容
  • 错误:RPC失败;(error: RPC failed; curl transfer closed with outstanding read data remaining)
  • C#类名中允许哪些字符?(What characters are allowed in C# class name?)
  • NumPy:将int64值存储在np.array中并使用dtype float64并将其转换回整数是否安全?(NumPy: Is it safe to store an int64 value in an np.array with dtype float64 and later convert it back to integer?)
  • 注销后如何隐藏导航portlet?(How to hide navigation portlet after logout?)
  • 将多个行和可变行移动到列(moving multiple and variable rows to columns)
  • 提交表单时忽略基础href,而不使用Javascript(ignore base href when submitting form, without using Javascript)
  • 对setOnInfoWindowClickListener的意图(Intent on setOnInfoWindowClickListener)
  • Angular $资源不会改变方法(Angular $resource doesn't change method)
  • 在Angular 5中不是一个函数(is not a function in Angular 5)
  • 如何配置Composite C1以将.m和桌面作为同一站点提供服务(How to configure Composite C1 to serve .m and desktop as the same site)
  • 不适用:悬停在悬停时:在元素之前[复制](Don't apply :hover when hovering on :before element [duplicate])
  • 常见的python rpc和cli接口(Common python rpc and cli interface)
  • Mysql DB单个字段匹配多个其他字段(Mysql DB single field matching to multiple other fields)
  • 产品页面上的Magento Up出售对齐问题(Magento Up sell alignment issue on the products page)