首页 \ 问答 \ JDK 7将自身报告为JRE(通过“java.home”系统属性)(JDK 7 reports itself as a JRE (via “java.home” system property))

JDK 7将自身报告为JRE(通过“java.home”系统属性)(JDK 7 reports itself as a JRE (via “java.home” system property))

我刚刚安装了最新的JDK 7 Update 21并编写了以下单行程序(在Windows 7上):

public static void main(String[] args) {
    System.out.println("java.home = " + System.getProperty("java.home"));
}

输出(令人惊讶):

java.home = D:\Java\jdk1.7.0_21\jre

我相信我解决了所有常见原因:

  1. JAVA_HOME设置为“D:\ Java \ jdk1.7.0_21”
  2. 我已将“D:\ Java \ jdk1.7.0_21 \ bin”设置为系统PATH设置中的第一个路径。
  3. Windows \ System32中没有java.exe
  4. 我正在使用“新鲜”的命令行
  5. 我已广泛搜索此网站和其他网站
  6. 我的注册表不包含“HKEY_LOCAL_MACHINE \ SOFTWARE \ JavaSoft \ Java运行时环境”键。 “HKEY_LOCAL_MACHINE \ SOFTWARE \ JavaSoft \ Java Development Kit \ 1.7”的值包含正确的“JavaHome”值。
  7. 在java.exe调用中添加“-server”选项不会更改输出

以下是您的信息的更多输出

D:\Temp>echo %PATH%
d:\Java\jdk1.7.0_21\bin

D:\Temp>echo %JAVA_HOME%
D:\Java\jdk1.7.0_21

D:\Temp>type SystemInfo.java
public class SystemInfo {

        public static void main(String[] args) {
                System.out.println("java.home = " + System.getProperty("java.home"));
        }

}

D:\Temp>java -verbose SystemInfo
[Opened d:\Java\jdk1.7.0_21\jre\lib\rt.jar]
[Loaded java.lang.Object from d:\Java\jdk1.7.0_21\jre\lib\rt.jar]
[Loaded java.io.Serializable from d:\Java\jdk1.7.0_21\jre\lib\rt.jar]
...
[Loaded java.lang.Void from d:\Java\jdk1.7.0_21\jre\lib\rt.jar]
java.home = d:\Java\jdk1.7.0_21\jre
[Loaded java.lang.Shutdown from d:\Java\jdk1.7.0_21\jre\lib\rt.jar]
[Loaded java.lang.Shutdown$Lock from d:\Java\jdk1.7.0_21\jre\lib\rt.jar]

(更新:) 基本上我需要知道,如何运行我的Java应用程序,以便它可以访问java编译器(在JDK的tools.jar中找到),而无需将JAR复制到其他地方。

顺便说一下,这背后的主要问题是我的码头无法编译JSP,因为缺少java编译器。 我知道我可以将“tools.jar”添加到JRE \ lib \ ext,但这不是一个长期的解决方案。


I just installed the latest JDK 7 Update 21 and wrote the following one-liner (on Windows 7):

public static void main(String[] args) {
    System.out.println("java.home = " + System.getProperty("java.home"));
}

the output is (surprisingly):

java.home = D:\Java\jdk1.7.0_21\jre

I believe I fixed all the common causes:

  1. JAVA_HOME is set to "D:\Java\jdk1.7.0_21"
  2. I have set "D:\Java\jdk1.7.0_21\bin" as the first path in the system PATH setting.
  3. There is no java.exe in Windows\System32
  4. I am using a "fresh" command-line
  5. I have searched this and other sites extensively
  6. My registry does not contain a "HKEY_LOCAL_MACHINE\SOFTWARE\JavaSoft\Java Runtime Environment" key. The value of "HKEY_LOCAL_MACHINE\SOFTWARE\JavaSoft\Java Development Kit\1.7" contains a correct "JavaHome" value.
  7. Adding "-server" option to the java.exe call does not change the output

Here is some more output for your information

D:\Temp>echo %PATH%
d:\Java\jdk1.7.0_21\bin

D:\Temp>echo %JAVA_HOME%
D:\Java\jdk1.7.0_21

D:\Temp>type SystemInfo.java
public class SystemInfo {

        public static void main(String[] args) {
                System.out.println("java.home = " + System.getProperty("java.home"));
        }

}

D:\Temp>java -verbose SystemInfo
[Opened d:\Java\jdk1.7.0_21\jre\lib\rt.jar]
[Loaded java.lang.Object from d:\Java\jdk1.7.0_21\jre\lib\rt.jar]
[Loaded java.io.Serializable from d:\Java\jdk1.7.0_21\jre\lib\rt.jar]
...
[Loaded java.lang.Void from d:\Java\jdk1.7.0_21\jre\lib\rt.jar]
java.home = d:\Java\jdk1.7.0_21\jre
[Loaded java.lang.Shutdown from d:\Java\jdk1.7.0_21\jre\lib\rt.jar]
[Loaded java.lang.Shutdown$Lock from d:\Java\jdk1.7.0_21\jre\lib\rt.jar]

(Updated:) Basically I need to know, how to run my java application so that it has access to the java-compiler (found in the JDK's tools.jar) without copying that JAR to some other place.

BTW the main problem behind this is that my jetty can't compile a JSP since the java-compiler is missing. I know I can add "tools.jar" to JRE\lib\ext but thats not a long-term solution.


原文:https://stackoverflow.com/questions/17061482
更新时间:2024-01-16 09:01

最满意答案

不,它在CSS和Stylus中是不可能的,因为它只是编译成CSS。

但是,在某些情况下,当你想要改变父看起来的样子时,你可以在某种程度上模仿它:你可以在类的一个元素后使用另一个元素,然后伸展到父类,看看这个演示: http:// dabblet的.com /要旨/ 7638112

您需要的HTML:

<ul>
<li><span class="correct">Ja</span><span class="helper"></span></li>
<li><span class="inCorrect">Nee</span><span class="helper"></span></li>
<li><span class="inCorrect">Mss</span><span class="helper"></span></li>
</ul>

和CSS:

li {
    position: relative;
    z-index: 1;
}

.helper {
    position: absolute;
    z-index: -1;
    top: 0;
    left: 0;
    right: 0;
    bottom: 0;
}

.correct + .helper {
    background: lime;
}

.inCorrect + .helper {
    background: red;
}

No, it is not possible in CSS, and in Stylus as it is just compiled into CSS.

However, you could somewhat emulate it in some cases, when you want to change just how the parent looks: you can use another element after the one with the class, and stretch in onto the parent, see this demo: http://dabblet.com/gist/7638112

The HTML you'd need there:

<ul>
<li><span class="correct">Ja</span><span class="helper"></span></li>
<li><span class="inCorrect">Nee</span><span class="helper"></span></li>
<li><span class="inCorrect">Mss</span><span class="helper"></span></li>
</ul>

and CSS:

li {
    position: relative;
    z-index: 1;
}

.helper {
    position: absolute;
    z-index: -1;
    top: 0;
    left: 0;
    right: 0;
    bottom: 0;
}

.correct + .helper {
    background: lime;
}

.inCorrect + .helper {
    background: red;
}

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