首页 \ 问答 \ 在Java中读取字符串(Reading String in java)

在Java中读取字符串(Reading String in java)

我一直在为学校编写这个代码来创建课程,用户,学生和老师,但是我在创建课程时遇到了一些障碍。

我想要做的是(在终端中)读取输入流,例如“CSC 110 Into to java”,并将其全部输入到字符串中。 我正在使用扫描仪进行输入。 并在next()之后尝试了hasNext()和nextLine()。 我想写一个函数来使用char数组获取整个字符串,然后将char数组转换为字符串。

首先我想知道是否有更简单的解决方案?

编辑:对不起,我不清楚。 没有进入我的所有代码。

目前代码:

        System.out.print("Enter the Course Title: ");
        title = keyboard.nextLine();
        System.out.print("Enter a Brief Course Description: ");
        desc = keyboard.nextLine();

        if (t != null)
        {   
            do
            {
                System.out.println("\nPick a teacher\n");

                for (int j = 0; j < t.size(); j++)
                {
                    nTeacher = t.get(j);
                    s += "\t(" + (j+1) + ") " + nTeacher + "\n";
                }

                System.out.print(s + "\nEnter the Teacher ID: ");
                int tId = keyboard.nextInt(); // My error

当前错误:

Enter the Course Title: CSC 110 Into to java

Enter a Breif Course Description: 
Pick a teacher

Enter the Teacher ID: 
Exception in thread "main" java.util.InputMismatchException
    at java.util.Scanner.throwFor(Scanner.java:857)
    at java.util.Scanner.next(Scanner.java:1478)
    at java.util.Scanner.nextInt(Scanner.java:2108)
    at java.util.Scanner.nextInt(Scanner.java:2067)
    at Prototype.classCreator(Prototype.java:530)
    at Prototype.mainMenu(Prototype.java:181)
    at Prototype.login(Prototype.java:121)
    at Prototype.main(Prototype.java:48)

当我使用nextLine()

Create Class
Enter the courseID: 27222
Enter the Course Title: Enter a Brief Course Description: 

预期结果:

Create Class
Enter the courseID: 27299
Enter the Course Title: CSC 110 Into to Java
Enter a Brief Course Description: Introduction to programming
Pick a teacher
(1) ID: 1111    Name: Bob
Enter the Teacher ID: 1
Class Created

我明白,当我有三个字符串“CSC 110 Intro”它得到nextInt()的输入,但我不明白为什么nextLine()正在写我的println是这样的。


I've been working on this code for school to create a course, users, students, and teachers but I ran into a snag while creating a course.

What I want to do is (in the terminal) read an input stream such as "CSC 110 Into to java" and enter all of it into a string. I am using Scanner for input. and have tried hasNext() and nextLine() besides next(). I thought about writing a function to use a char array get the entire string and then convert the char array into a string.

First I wanted to know if there was an easier solution?

Edit: Sorry I wasn't clear. Without going into all of my code.

current Code:

        System.out.print("Enter the Course Title: ");
        title = keyboard.nextLine();
        System.out.print("Enter a Brief Course Description: ");
        desc = keyboard.nextLine();

        if (t != null)
        {   
            do
            {
                System.out.println("\nPick a teacher\n");

                for (int j = 0; j < t.size(); j++)
                {
                    nTeacher = t.get(j);
                    s += "\t(" + (j+1) + ") " + nTeacher + "\n";
                }

                System.out.print(s + "\nEnter the Teacher ID: ");
                int tId = keyboard.nextInt(); // My error

Current error:

Enter the Course Title: CSC 110 Into to java

Enter a Breif Course Description: 
Pick a teacher

Enter the Teacher ID: 
Exception in thread "main" java.util.InputMismatchException
    at java.util.Scanner.throwFor(Scanner.java:857)
    at java.util.Scanner.next(Scanner.java:1478)
    at java.util.Scanner.nextInt(Scanner.java:2108)
    at java.util.Scanner.nextInt(Scanner.java:2067)
    at Prototype.classCreator(Prototype.java:530)
    at Prototype.mainMenu(Prototype.java:181)
    at Prototype.login(Prototype.java:121)
    at Prototype.main(Prototype.java:48)

When I use nextLine()

Create Class
Enter the courseID: 27222
Enter the Course Title: Enter a Brief Course Description: 

Intended result:

Create Class
Enter the courseID: 27299
Enter the Course Title: CSC 110 Into to Java
Enter a Brief Course Description: Introduction to programming
Pick a teacher
(1) ID: 1111    Name: Bob
Enter the Teacher ID: 1
Class Created

I understand that when I have three strings "CSC 110 Intro" it get to the input for nextInt() but I don't understand why nextLine() is writing my println's like this.


原文:https://stackoverflow.com/questions/5534704
更新时间:2022-08-22 10:08

最满意答案

您可以使用Visual Studio Gallery中的 VSCommands Lite扩展(免费)

在这里输入图像描述


You can use VSCommands Lite extension (free) from Visual Studio Gallery

enter image description here

相关问答

更多

相关文章

更多

最新问答

更多
  • 您如何使用git diff文件,并将其应用于同一存储库的副本的本地分支?(How do you take a git diff file, and apply it to a local branch that is a copy of the same repository?)
  • 将长浮点值剪切为2个小数点并复制到字符数组(Cut Long Float Value to 2 decimal points and copy to Character Array)
  • OctoberCMS侧边栏不呈现(OctoberCMS Sidebar not rendering)
  • 页面加载后对象是否有资格进行垃圾回收?(Are objects eligible for garbage collection after the page loads?)
  • codeigniter中的语言不能按预期工作(language in codeigniter doesn' t work as expected)
  • 在计算机拍照在哪里进入
  • 使用cin.get()从c ++中的输入流中丢弃不需要的字符(Using cin.get() to discard unwanted characters from the input stream in c++)
  • No for循环将在for循环中运行。(No for loop will run inside for loop. Testing for primes)
  • 单页应用程序:页面重新加载(Single Page Application: page reload)
  • 在循环中选择具有相似模式的列名称(Selecting Column Name With Similar Pattern in a Loop)
  • System.StackOverflow错误(System.StackOverflow error)
  • KnockoutJS未在嵌套模板上应用beforeRemove和afterAdd(KnockoutJS not applying beforeRemove and afterAdd on nested templates)
  • 散列包括方法和/或嵌套属性(Hash include methods and/or nested attributes)
  • android - 如何避免使用Samsung RFS文件系统延迟/冻结?(android - how to avoid lag/freezes with Samsung RFS filesystem?)
  • TensorFlow:基于索引列表创建新张量(TensorFlow: Create a new tensor based on list of indices)
  • 企业安全培训的各项内容
  • 错误:RPC失败;(error: RPC failed; curl transfer closed with outstanding read data remaining)
  • C#类名中允许哪些字符?(What characters are allowed in C# class name?)
  • NumPy:将int64值存储在np.array中并使用dtype float64并将其转换回整数是否安全?(NumPy: Is it safe to store an int64 value in an np.array with dtype float64 and later convert it back to integer?)
  • 注销后如何隐藏导航portlet?(How to hide navigation portlet after logout?)
  • 将多个行和可变行移动到列(moving multiple and variable rows to columns)
  • 提交表单时忽略基础href,而不使用Javascript(ignore base href when submitting form, without using Javascript)
  • 对setOnInfoWindowClickListener的意图(Intent on setOnInfoWindowClickListener)
  • Angular $资源不会改变方法(Angular $resource doesn't change method)
  • 在Angular 5中不是一个函数(is not a function in Angular 5)
  • 如何配置Composite C1以将.m和桌面作为同一站点提供服务(How to configure Composite C1 to serve .m and desktop as the same site)
  • 不适用:悬停在悬停时:在元素之前[复制](Don't apply :hover when hovering on :before element [duplicate])
  • 常见的python rpc和cli接口(Common python rpc and cli interface)
  • Mysql DB单个字段匹配多个其他字段(Mysql DB single field matching to multiple other fields)
  • 产品页面上的Magento Up出售对齐问题(Magento Up sell alignment issue on the products page)