首页 \ 问答 \ Java Solr SolrJ获取新建索引文件的id值(Java Solr SolrJ get id value of the newly indexed file)

Java Solr SolrJ获取新建索引文件的id值(Java Solr SolrJ get id value of the newly indexed file)

我有一个实体,我想链接到通过SolrJ上传到solr的索引文件。 最好它是实体上的一个字段,其文件的条目标识为值。 事情是 - 我不知道如何在上传之后获得该ID。 代码如下:

            //File tempFile;
            //MultipartFile file;
            tempFile = File.createTempFile(prefix, postfix);
            file.transferTo(tempFile);
            ContentStreamUpdateRequest req = new ContentStreamUpdateRequest("/update/extract");
            req.addFile(tempFile, file.getContentType());
            req.setAction(AbstractUpdateRequest.ACTION.COMMIT, true, true);
            NamedList list = solrClient.request(req);
            System.out.println(list);
            //{responseHeader={status=0,QTime=1328}}
            tempFile.delete();

I have an entity, which I want to link to an indexed file uploaded to solr via SolrJ. Preferably it would be a field on the entity with the file's entry id as value. Thing is - I don't know how to get that id after it just being uploaded. Here is the code:

            //File tempFile;
            //MultipartFile file;
            tempFile = File.createTempFile(prefix, postfix);
            file.transferTo(tempFile);
            ContentStreamUpdateRequest req = new ContentStreamUpdateRequest("/update/extract");
            req.addFile(tempFile, file.getContentType());
            req.setAction(AbstractUpdateRequest.ACTION.COMMIT, true, true);
            NamedList list = solrClient.request(req);
            System.out.println(list);
            //{responseHeader={status=0,QTime=1328}}
            tempFile.delete();

原文:https://stackoverflow.com/questions/42250674
更新时间:2019-12-27 12:46

最满意答案

我已经尝试了这个并且似乎工作正常,因为我怀疑语法和逻辑看起来是正确的。 您可以尝试添加对ToList的调用,这将使其在检查它是一个整数列表时更加清晰。 如果没有,那么肯定会有其他事情发生。 这是我建议的代码:

IEnumerable<int> rpList = dataBits
.Where(bit => bit.bitPos > 2)
.Select(bit => bit.risePeriod)
.ToList();

I've tried this and it seems to be working fine, as I suspected as the syntax and logic looks correct. You could try adding a call to ToList which will make it more clear when inspected that it is a list of integers. If not, there must be something else going on here. Here's the code I suggest:

IEnumerable<int> rpList = dataBits
.Where(bit => bit.bitPos > 2)
.Select(bit => bit.risePeriod)
.ToList();

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