在JavaScript中如何将像素转换为英寸？(How do you convert pixels to printed inches in JavaScript?)

 您的代码不完整。 
 
 你接缝就像这样调用你的函数： 
 
c = [[3], [1], [4], [5], [7], [0], [2], [6]]
p = [[0, 1, 2, 4, 5, 6, 7],
     [0, 2, 3, 4, 5, 6, 7],
     [0, 1, 2, 3, 6, 7, 4],
     [0, 1, 2, 3, 6, 5, 5],
     [0, 1, 2, 3, 4, 6, 7],
     [1, 2, 3, 4, 6, 7, 5],
     [0, 1, 3, 4, 5, 6, 7],
     [0, 1, 2, 3, 4, 5, 7]]

for i in range(1000):
    c_main, p_main = temp(c, p)
 
 注意：如果修复了你的代码：添加range并为p中的每一行添加逗号。 
 
 但是在你的temp()函数中，你正在修改p的内容。 所以，你可能没有你期望的。 因为在每次迭代时都重复使用相同的p 。 所以有时它会变得不一致。 
 
 你想要什么，当然是这样的： 
 
import random

def temp(c):
    # -- raw matrix
    p = [[col for col in range(8)] for row in range(len(c))]

    # -- drop a number
    for p_row, c_row in zip(p, c):
        p_row.pop(c_row[0])

    # -- shuffle
    for row in p:
        random.shuffle(row)

    return p
 
 你可以像这样使用它： 
 
cols = [[3], [1], [4], [5], [7], [0], [2], [6]]
print(temp(cols))
 
 你得到： 
 
[[6, 1, 4, 5, 7, 2, 0],
 [3, 0, 5, 4, 2, 7, 6],
 [2, 7, 0, 3, 6, 5, 1],
 [1, 2, 7, 4, 6, 3, 0],
 [3, 1, 4, 6, 2, 0, 5],
 [4, 5, 6, 3, 7, 1, 2],
 [0, 6, 1, 5, 7, 3, 4],
 [4, 3, 7, 0, 1, 5, 2]]

Your code is not complete.
 
You seam to call your function like this:
 
c = [[3], [1], [4], [5], [7], [0], [2], [6]]
p = [[0, 1, 2, 4, 5, 6, 7],
     [0, 2, 3, 4, 5, 6, 7],
     [0, 1, 2, 3, 6, 7, 4],
     [0, 1, 2, 3, 6, 5, 5],
     [0, 1, 2, 3, 4, 6, 7],
     [1, 2, 3, 4, 6, 7, 5],
     [0, 1, 3, 4, 5, 6, 7],
     [0, 1, 2, 3, 4, 5, 7]]

for i in range(1000):
    c_main, p_main = temp(c, p)
 
note: if fixed your code: add range and add comma for each lines in p.
 
But inside your temp() function, your are modifying the content of p. So, you may not have what you expect. Because you reuse the same p at each iteration. So sometimes it becomes inconsistent.
 
What you want, is certainly something like that:
 
import random

def temp(c):
    # -- raw matrix
    p = [[col for col in range(8)] for row in range(len(c))]

    # -- drop a number
    for p_row, c_row in zip(p, c):
        p_row.pop(c_row[0])

    # -- shuffle
    for row in p:
        random.shuffle(row)

    return p
 
You can use it like this:
 
cols = [[3], [1], [4], [5], [7], [0], [2], [6]]
print(temp(cols))
 
You get:
 
[[6, 1, 4, 5, 7, 2, 0],
 [3, 0, 5, 4, 2, 7, 6],
 [2, 7, 0, 3, 6, 5, 1],
 [1, 2, 7, 4, 6, 3, 0],
 [3, 1, 4, 6, 2, 0, 5],
 [4, 5, 6, 3, 7, 1, 2],
 [0, 6, 1, 5, 7, 3, 4],
 [4, 3, 7, 0, 1, 5, 2]]