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JavaScript / jQuery为什么这不起作用?(JavaScript / jQuery why doesn't this work?)

function checkSession(){
    $.ajax({url: "session.php", success: function(data){
         if( data == 1){
             var postFilen = 'msg.php';
             $.post(postFilen, function(data){
                 $("#msg").html(data).find("#message2").fadeIn("slow")
            }
         } else {
             $('#message2').hide();
         }
    }});
// setInterval('checkSession()',1000);
}

基本上,这是在session.php中检查数据是否为1,如果是,它应该在#msg中运行msg.php的div#message2


function checkSession(){
    $.ajax({url: "session.php", success: function(data){
         if( data == 1){
             var postFilen = 'msg.php';
             $.post(postFilen, function(data){
                 $("#msg").html(data).find("#message2").fadeIn("slow")
            }
         } else {
             $('#message2').hide();
         }
    }});
// setInterval('checkSession()',1000);
}

Basically, this is checking if data is 1 in session.php, and if it is, it should run msg.php´s div #message2 in #msg


原文:https://stackoverflow.com/questions/2329860
更新时间:2023-06-21 16:06

最满意答案

由于one是ArrayList,因此只能将它作为参考传递。 你现在显然将它作为引用来引用构造函数。 你可能不需要那个ref

但是请展示你想要完成的更完整的想法。

编辑:

看完你的C课后,不需要refc将共享A调用的ArrayList的实例。

这似乎归结为.NET中的一般referencetype / valuetype问题。 总结:

  • 对象的实例没有名称,并且根本无法(物理上)作为参数传递。
  • 你总是通过引用访问实例。 在你的代码中, one (2x), two local都是对Arraylist实例的引用。
  • 引用本身的行为类似于值类型,即赋值意味着复制。

要了解有关referencetypes / valuetypes的更多信息,请搜索“复制语义”,并避免以'valueetypes存在于堆栈中'为开头的帖子。


Since one is an ArrayList, you can only pass it as a reference. You are now apparently passing it as a reference-to-a-reference to the constructor. You may not need that ref.

But please show a more complete idea of what you are trying to accomplish.

Edit:

After seeing your C class, there is no need for the ref. c will share the instance of the ArrayList that A calls one.

This seems to boil down to the general referencetype/valuetype issue in .NET. To summarize:

  • instances of objects do not have a name and cannot (physically) be passed as parameter at all.
  • you always access an instance through a reference. In your code, one (2x) , two, local are all references to Arraylist instances.
  • the references themselves behave like valuetypes, ie assignment means copying.

To learn more about referencetypes/valuetypes, search for 'copy semantics' and avoid postings that start with 'valuetypes exist on the stack'.

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