如何使用Javascript跟踪出站点击(How To Track Outbound Clicks Using Javascript)

 我正在尝试使用此处提供的代码： 在不重定向的情况下ping一个url 。 OP已经要求在不打开多个窗口的情况下ping网址。 我想这样做，但我想实际访问第二个网址，以便我可以跟踪我的服务器分析中的出站点击。 
 
 这是我正在尝试的代码： 
 
<a href="javascript:;" onclick="visitPageX()">link</a>

function visitPageX() {
  // send Ajax request to the track URL
  setTimeout(function() {
    location.href = 'http://{pageXURL}';
  }, 300);
}
 
 但是，我不明白我应该把我的“跟踪网址”放在哪里。 这是我的尝试： 
 
<a href="javascript:;" onclick="visitPageX()"><a href="http://externalsite.com/">anchor text</a></a>

function visitPageX() {
  // send Ajax request to the track URL
  setTimeout(function() {
    location.href = 'http://externalsite.com/';
  }, 300);
}
 
 我坚持要放在哪里 
 
http://examplemysite.com/tracking.php?123
 
 这样我就可以计算出站点击次数。 如果您可以帮助我使用此代码，或者提供更好的解决方案来跟踪外出点击而无需使用Google Analytics，我将不胜感激。 
 
 非常感谢您的支持。 

I am trying to use the code provided here: Make a ping to a url without redirecting. The OP has asked to ping a url without opening multiple windows. I would like to do this, but I want to actually visit a second url so I can track the outbound clicks in my server analytics.
 
Here's the code I'm trying to make work:
 
<a href="javascript:;" onclick="visitPageX()">link</a>

function visitPageX() {
  // send Ajax request to the track URL
  setTimeout(function() {
    location.href = 'http://{pageXURL}';
  }, 300);
}
 
However, I don't understand where I should be putting my "tracking url". Here's my attempt at it:
 
<a href="javascript:;" onclick="visitPageX()"><a href="http://externalsite.com/">anchor text</a></a>

function visitPageX() {
  // send Ajax request to the track URL
  setTimeout(function() {
    location.href = 'http://externalsite.com/';
  }, 300);
}
 
I'm stuck at where to put 
 
http://examplemysite.com/tracking.php?123
 
so that I can count the outbound clicks. I would appreciate it if you could help me get this code working or provide an even better solution to tracking outbound clicks without using Google Analytics. 
 
Your support is very much appreciated. 

原文：https://stackoverflow.com/questions/46851955