Java JFreeChart类别步骤图水平(图像解释)(Java JFreeChart Category Step Chart horizontal (image to explane))
我需要以下类型的图表:
它应该是一个“竖立”的折线图,纵轴上有类别,如下所示:我发现这个类别步骤图的例子,但它的方向不适合我的目的。
到目前为止,我所做的只是这一点,但正如你所看到的,红线不适合图表的方向(应该是水平的):相应的代码如下:
DefaultCategoryDataset ds = new DefaultCategoryDataset(); // create dataset for (int k = 0; k < ffCount; k++) { StateSignal ss1 = (StateSignal) this.ffDSet.getFframes().get(k).getSignals().get(i); ds.setValue((double) k + 1, ss1.getName(), ss1.getStates().get(0).getStatus()); } CategoryStepRenderer categorysteprenderer = new CategoryStepRenderer(false); categorysteprenderer.setBaseToolTipGenerator(new StandardCategoryToolTipGenerator()); CategoryAxis categoryaxis = new CategoryAxis("Category"); NumberAxis numberaxis = new NumberAxis("Value"); CategoryPlot categoryplot = new CategoryPlot(ds, categoryaxis, numberaxis, categorysteprenderer); categoryplot.setRangePannable(true); categoryplot.setOrientation(PlotOrientation.HORIZONTAL); chart = new JFreeChart("test", null, categoryplot, true);
我没有得到它的工作。 有任何想法吗?
提前致谢!
i need the following type of chart:
It should be a "steped" line chart with categories on the vertical axis, like this:I found this example of an Category Step Chart, but it the orientation is not right for my purpose.
All i have done so far is this, but as you can see the red line does not fit to the orientation of the chart(should be horizontal):
The corresponding code to this:
DefaultCategoryDataset ds = new DefaultCategoryDataset(); // create dataset for (int k = 0; k < ffCount; k++) { StateSignal ss1 = (StateSignal) this.ffDSet.getFframes().get(k).getSignals().get(i); ds.setValue((double) k + 1, ss1.getName(), ss1.getStates().get(0).getStatus()); } CategoryStepRenderer categorysteprenderer = new CategoryStepRenderer(false); categorysteprenderer.setBaseToolTipGenerator(new StandardCategoryToolTipGenerator()); CategoryAxis categoryaxis = new CategoryAxis("Category"); NumberAxis numberaxis = new NumberAxis("Value"); CategoryPlot categoryplot = new CategoryPlot(ds, categoryaxis, numberaxis, categorysteprenderer); categoryplot.setRangePannable(true); categoryplot.setOrientation(PlotOrientation.HORIZONTAL); chart = new JFreeChart("test", null, categoryplot, true);
I don´t get it to work. Any ideas?
Thanks in advance!
原文:https://stackoverflow.com/questions/12835369
最满意答案
我认为_blank更改是最新的,尚未在iOS中实现。 我目前在
AppDelegate.m
使用这段本机代码在Safari中打开外部URL- (BOOL) webView:(UIWebView*)theWebView shouldStartLoadWithRequest:(NSURLRequest*)request navigationType:(UIWebViewNavigationType)navigationType { //return [self.viewController webView:theWebView shouldStartLoadWithRequest:request navigationType:navigationType]; NSURL *url = [request URL]; // Intercept the external http requests and forward to Safari.app // Otherwise forward to the PhoneGap WebView if ([[url scheme] isEqualToString:@"http"] || [[url scheme] isEqualToString:@"https"] || [[url scheme] isEqualToString:@"itms-apps"]) { [[UIApplication sharedApplication] openURL:url]; return NO; } else { return [self.viewController webView:theWebView shouldStartLoadWithRequest:request navigationType:navigationType]; } }
I think the _blank change is a recent one and not yet implemented in iOS. I currently use this piece of native code in
AppDelegate.m
to open external URLs in Safari- (BOOL) webView:(UIWebView*)theWebView shouldStartLoadWithRequest:(NSURLRequest*)request navigationType:(UIWebViewNavigationType)navigationType { //return [self.viewController webView:theWebView shouldStartLoadWithRequest:request navigationType:navigationType]; NSURL *url = [request URL]; // Intercept the external http requests and forward to Safari.app // Otherwise forward to the PhoneGap WebView if ([[url scheme] isEqualToString:@"http"] || [[url scheme] isEqualToString:@"https"] || [[url scheme] isEqualToString:@"itms-apps"]) { [[UIApplication sharedApplication] openURL:url]; return NO; } else { return [self.viewController webView:theWebView shouldStartLoadWithRequest:request navigationType:navigationType]; } }
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