首页 \ 问答 \ Java JFreeChart类别步骤图水平(图像解释)(Java JFreeChart Category Step Chart horizontal (image to explane))

Java JFreeChart类别步骤图水平(图像解释)(Java JFreeChart Category Step Chart horizontal (image to explane))


我需要以下类型的图表:
它应该是一个“竖立”的折线图,纵轴上有类别,如下所示:

这就是它所表现的

我发现这个类别步骤图的例子,但它的方向不适合我的目的。

http://www.jfree.org/jfreechart/api/javadoc/org/jfree/chart/renderer/category/CategoryStepRenderer.html


到目前为止,我所做的只是这一点,但正如你所看到的,红线不适合图表的方向(应该是水平的):

当前状态

相应的代码如下:

   DefaultCategoryDataset ds = new DefaultCategoryDataset(); 

// create dataset

    for (int k = 0; k < ffCount; k++) {
                  StateSignal ss1 = (StateSignal) this.ffDSet.getFframes().get(k).getSignals().get(i);
                  ds.setValue((double) k + 1, ss1.getName(), ss1.getStates().get(0).getStatus());

     }
    CategoryStepRenderer categorysteprenderer = new CategoryStepRenderer(false);
    categorysteprenderer.setBaseToolTipGenerator(new StandardCategoryToolTipGenerator());
    CategoryAxis categoryaxis = new CategoryAxis("Category");
    NumberAxis numberaxis = new NumberAxis("Value");
    CategoryPlot categoryplot = new CategoryPlot(ds, categoryaxis, numberaxis, categorysteprenderer);
    categoryplot.setRangePannable(true);
    categoryplot.setOrientation(PlotOrientation.HORIZONTAL);
    chart = new JFreeChart("test", null, categoryplot, true);

我没有得到它的工作。 有任何想法吗?

提前致谢!



i need the following type of chart:
It should be a "steped" line chart with categories on the vertical axis, like this:

this is how it shold be

I found this example of an Category Step Chart, but it the orientation is not right for my purpose.

http://www.jfree.org/jfreechart/api/javadoc/org/jfree/chart/renderer/category/CategoryStepRenderer.html


All i have done so far is this, but as you can see the red line does not fit to the orientation of the chart(should be horizontal):

current state

The corresponding code to this:

   DefaultCategoryDataset ds = new DefaultCategoryDataset(); 

// create dataset

    for (int k = 0; k < ffCount; k++) {
                  StateSignal ss1 = (StateSignal) this.ffDSet.getFframes().get(k).getSignals().get(i);
                  ds.setValue((double) k + 1, ss1.getName(), ss1.getStates().get(0).getStatus());

     }
    CategoryStepRenderer categorysteprenderer = new CategoryStepRenderer(false);
    categorysteprenderer.setBaseToolTipGenerator(new StandardCategoryToolTipGenerator());
    CategoryAxis categoryaxis = new CategoryAxis("Category");
    NumberAxis numberaxis = new NumberAxis("Value");
    CategoryPlot categoryplot = new CategoryPlot(ds, categoryaxis, numberaxis, categorysteprenderer);
    categoryplot.setRangePannable(true);
    categoryplot.setOrientation(PlotOrientation.HORIZONTAL);
    chart = new JFreeChart("test", null, categoryplot, true);

I don´t get it to work. Any ideas?

Thanks in advance!


原文:https://stackoverflow.com/questions/12835369
更新时间:2023-07-12 21:07

最满意答案

我认为_blank更改是最新的,尚未在iOS中实现。 我目前在AppDelegate.m使用这段本机代码在Safari中打开外部URL

- (BOOL) webView:(UIWebView*)theWebView shouldStartLoadWithRequest:(NSURLRequest*)request navigationType:(UIWebViewNavigationType)navigationType
{
    //return [self.viewController webView:theWebView shouldStartLoadWithRequest:request navigationType:navigationType];
    NSURL *url = [request URL];

    // Intercept the external http requests and forward to Safari.app
    // Otherwise forward to the PhoneGap WebView
    if ([[url scheme] isEqualToString:@"http"] || [[url scheme] isEqualToString:@"https"] || [[url scheme] isEqualToString:@"itms-apps"]) {
        [[UIApplication sharedApplication] openURL:url];
        return NO;
    }
    else {
        return [self.viewController webView:theWebView shouldStartLoadWithRequest:request navigationType:navigationType];
    }
}

I think the _blank change is a recent one and not yet implemented in iOS. I currently use this piece of native code in AppDelegate.m to open external URLs in Safari

- (BOOL) webView:(UIWebView*)theWebView shouldStartLoadWithRequest:(NSURLRequest*)request navigationType:(UIWebViewNavigationType)navigationType
{
    //return [self.viewController webView:theWebView shouldStartLoadWithRequest:request navigationType:navigationType];
    NSURL *url = [request URL];

    // Intercept the external http requests and forward to Safari.app
    // Otherwise forward to the PhoneGap WebView
    if ([[url scheme] isEqualToString:@"http"] || [[url scheme] isEqualToString:@"https"] || [[url scheme] isEqualToString:@"itms-apps"]) {
        [[UIApplication sharedApplication] openURL:url];
        return NO;
    }
    else {
        return [self.viewController webView:theWebView shouldStartLoadWithRequest:request navigationType:navigationType];
    }
}

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