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Java:访问ANY模块之外的相对路径(Java: Access relative path outside ANY module)

我有一个由几个模块组成的java项目:

myWebApp
  - conf     //not a java module, just text files
  - ModuleA
      -- src
      -- target
      -- moduleA.iml
      -- pom.xml
  - ModuleB
     ...
  - pom.xml
  - myWebApp.iml
  - myWebApp.env

我想从一个Class(显然在模块的src文件夹下)访问myWebApp.env文件(这是一个java属性文件),如:

InputStream is = new FileInputStream(<RelativePathToEnvFile>);

问题是相对路径似乎仅适用于模块源根目录下的子目录,或者使用此处提到的getResource()技巧在类路径内的任何位置工作

在其他所有语言中,我知道我可以做以下事情:

InputStream is = new FileInputStream("../../../../../myWebApp.env");

这不可能在java中吗?


I have a java project that consists of several modules:

myWebApp
  - conf     //not a java module, just text files
  - ModuleA
      -- src
      -- target
      -- moduleA.iml
      -- pom.xml
  - ModuleB
     ...
  - pom.xml
  - myWebApp.iml
  - myWebApp.env

I want to access myWebApp.env file (which is a java properties file) from a Class (which is obviously under a module's src folder), like:

InputStream is = new FileInputStream(<RelativePathToEnvFile>);

The problem is that relative paths seem to work only for subdirectories under modules' source root, or anywhere inside the classpath using the getResource() trick as mentioned here

On every other language I know I could do something like:

InputStream is = new FileInputStream("../../../../../myWebApp.env");

Isn't this possible in java?


原文:
更新时间:2021-08-30 10:08

最满意答案

你不能使用appendRow做你想要的。 您正在使用:

target_sheet.appendRow(data);

你需要使用setValues()

target_sheet(start row, start column, number of rows, number of columns).setValues(data);

在您的情况下,如果要覆盖(编辑)现有行,则需要在其中找到包含索引的行,并将该数字用于start row参数。

var data, dataAs1D,dataFromCol1,ouss, target_sheet, lastRow,rowToEdit;

ss = SpreadsheetApp.getActiveSpreadsheet();
target_sheet = ss.getSheetByName('name');

lastRow = target_sheet.getLastRow();

dataFromCol1 = target_sheet.getRange(1,1,lastRow,1).getValues();//Get all col A values
dataAs1D = dataFromCol1.toString().split(",");//Convert 2D array to 1D

rowToEdit = colorRow;//

data = ['one','two','three'];
outerArray = [];//Assign empty array to variable name
outerArray.push(data);
target_sheet.getRange(rowToEdit,1,data[0].length,data.length).setValues(data);

此示例假定您的索引号位于第一列。


You can not use appendRow to do what you want. You are using:

target_sheet.appendRow(data);

You need to use setValues()

target_sheet(start row, start column, number of rows, number of columns).setValues(data);

In your case, if you want to overwrite (edit) an existing row, then you will need to find the row with the index in it, and use that number for the start row parameter.

var data, dataAs1D,dataFromCol1,ouss, target_sheet, lastRow,rowToEdit;

ss = SpreadsheetApp.getActiveSpreadsheet();
target_sheet = ss.getSheetByName('name');

lastRow = target_sheet.getLastRow();

dataFromCol1 = target_sheet.getRange(1,1,lastRow,1).getValues();//Get all col A values
dataAs1D = dataFromCol1.toString().split(",");//Convert 2D array to 1D

rowToEdit = colorRow;//

data = ['one','two','three'];
outerArray = [];//Assign empty array to variable name
outerArray.push(data);
target_sheet.getRange(rowToEdit,1,data[0].length,data.length).setValues(data);

This example assumes that your index numbers are in column one.

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