首页 \ 问答 \ 为什么[import java.awt。*]不包含[import java.awt.event.ActionEvent]?(Why does [import java.awt.*] not also include [import java.awt.event.ActionEvent]?)

为什么[import java.awt。*]不包含[import java.awt.event.ActionEvent]?(Why does [import java.awt.*] not also include [import java.awt.event.ActionEvent]?)

晚间,

我正在玩一个小摇摆应用程序,并且我添加了一个按钮来响应被按下。 因此我需要实现ActionListener。 我已经添加了这一行:

import java.awt.*;

但它告诉我它找不到“ActionListener”类。 所以过了一会儿,我结束了这个:

import java.awt.*;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;

我假设awt。*部分意味着它将在awt伞下导入所有子包。 显然情况并非如此。 有人能为我澄清这个问题吗?


Evening,

I was playing around with a little swing application, and I added a button which was to respond to being pressed. Therefore I needed to implement ActionListener. I had already added this line:

import java.awt.*;

but it informed me that it could not find the "ActionListener" class. So after a few moments I ended up with this:

import java.awt.*;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;

I was under the assumption that the awt.* part meant that it was importing all sub-packages under the awt umbrella. Apparently this isn't the case. Can someone please clarify this problem for me?


原文:https://stackoverflow.com/questions/11627001
更新时间:2023-09-12 08:09

最满意答案

这是您如何使用MemoryStream创建新的电子表格文档,然后将其保存为Byte[]

Byte[] file;
using (MemoryStream mem = new MemoryStream())
{
    using (SpreadsheetDocument spreadsheetDocument = 
        SpreadsheetDocument.Create(mem, SpreadsheetDocumentType.Workbook))
    {
        WorkbookPart workbookpart = spreadsheetDocument.AddWorkbookPart();
        workbookpart.Workbook = new Workbook();
        WorksheetPart worksheetPart = workbookpart.AddNewPart<WorksheetPart>();
        worksheetPart.Worksheet = new Worksheet(new SheetData());

        Sheets sheets = spreadsheetDocument.WorkbookPart.Workbook.
            AppendChild<Sheets>(new Sheets());

        Sheet sheet = new Sheet()
        {
            Id = spreadsheetDocument.WorkbookPart.
                GetIdOfPart(worksheetPart),
            SheetId = 1,
            Name = "aStupidSheet"
        };
        sheets.Append(sheet);
        workbookpart.Workbook.Save()
        spreadsheetDocument.Close();
    }
    file = mem.ToArray();
}

With the help from FortyTwo I managed to achieve my goal.

So the desired "workflow" is:

  1. copy .docx template (added headers or other things) to memory
  2. edit content of the document
  3. return this document as FileResult without saving the changes to template

So here is the code:

public FileResult EditDOCXBody()
{
    // Prepare file path
    string file = "../WordTemplates/EmptyTemplate.docx";
    String fullFilePath = HttpContext.ApplicationInstance.Server.MapPath(file);                   

    // Copy file content to MemeoryStream via byte array
    MemoryStream stream = new MemoryStream();                          
    byte[] fileBytesArray = System.IO.File.ReadAllBytes(fullFilePath);  
    stream.Write(fileBytesArray, 0, fileBytesArray.Length);             // copy file content to MemoryStream
    stream.Position = 0;                                                

    // Edit word document content
    using (WordprocessingDocument wordDoc = WordprocessingDocument.Open(stream, true))  
    {
        MainDocumentPart mainPart = wordDoc.MainDocumentPart;                
        Body body = mainPart.Document.Body;

        // add some text to body
        body.Append(new Paragraph(
                    new Run(
                        new Text("Current time is: " + DateTime.Now.ToLongTimeString()))));

        // Save changes to reflect on stream object
        mainPart.Document.Save();                
    }
    return File(stream.ToArray(), "application/vnd.openxmlformats-officedocument.wordprocessingml.document", "servedFilename.docx");            
}

Some important notes:

  • you need to write file bytes to MemoryStream manually otherwise you get Memory stream is not expandable error. More info here
  • you have to use mainPart.Document.Save() for changes to take effect on MemoryStream
  • when returning the file, you have to use .ToArray() otherwise the returned file is corrupted

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