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ifstream与fread的二进制文件(ifstream vs. fread for binary files)

哪个更快? ifstreamfread
我应该用哪个来读取二进制文件?

fread()将整个文件放入内存中。
所以在fread之后,访问它创建的缓冲区很快。

ifstream::open()是否将整个文件放入内存?
或者每次运行ifstream::read()时它是否访问硬盘?

那么...... ifstream::open() == fread()吗?
或( ifstream::open(); ifstream::read(file_length); )== fread()

或者我应该使用ifstream::rdbuf()->read()

编辑:我的readFile()方法现在看起来像这样:

void readFile()
{
    std::ifstream fin;
    fin.open("largefile.dat", ifstream::binary | ifstream::in);
    // in each of these small read methods, there are at least 1 fin.read()
    // call inside.
    readHeaderInfo(fin);
    readPreference(fin);
    readMainContent(fin);
    readVolumeData(fin);
    readTextureData(fin);
    fin.close();
}

使用小方法的多个fin.read()调用会减慢程序吗? 我只能在main方法中使用1个fin.read()并将缓冲区传递给小方法吗? 我想我打算写一个小程序进行测试。

谢谢!


Which is faster? ifstream or fread.
Which should I use to read binary files?

fread() puts the whole file into the memory.
So after fread, accessing the buffer it creates is fast.

Does ifstream::open() puts the whole file into the memory?
or does it access the hard disk every time we run ifstream::read()?

So... does ifstream::open() == fread()?
or (ifstream::open(); ifstream::read(file_length);) == fread()?

Or shall I use ifstream::rdbuf()->read()?

edit: My readFile() method now looks something like this:

void readFile()
{
    std::ifstream fin;
    fin.open("largefile.dat", ifstream::binary | ifstream::in);
    // in each of these small read methods, there are at least 1 fin.read()
    // call inside.
    readHeaderInfo(fin);
    readPreference(fin);
    readMainContent(fin);
    readVolumeData(fin);
    readTextureData(fin);
    fin.close();
}

Will the multiple fin.read() calls in the small methods slow down the program? Shall I only use 1 fin.read() in the main method and pass the buffer into the small methods? I guess I am going to write a small program to test.

Thanks!


原文:https://stackoverflow.com/questions/6131307
更新时间:2022-04-03 16:04

最满意答案

样品

#include <stdio.h>
#include <stdlib.h>

#define N 4
#define M 3

int main()
{
    int *Ptr;
    int (*p)[M];
    int i,j;

    Ptr = malloc(M*N*sizeof(int));

    for (i = 0; i < M * N; i++){
        *(Ptr + i) = 1 + rand()%10;
//      printf("%d ", Ptr[i]);
    }
//  printf("\n");

    p=(int (*)[M])Ptr;//p[N][M]
    for(i = 0; i < N ;++i){
        for(j = 0; j < M;++j)
            printf("%d ", p[i][j]);
        printf("\n");
    }

   return 0;
}

Sample

#include <stdio.h>
#include <stdlib.h>

#define N 4
#define M 3

int main()
{
    int *Ptr;
    int (*p)[M];
    int i,j;

    Ptr = malloc(M*N*sizeof(int));

    for (i = 0; i < M * N; i++){
        *(Ptr + i) = 1 + rand()%10;
//      printf("%d ", Ptr[i]);
    }
//  printf("\n");

    p=(int (*)[M])Ptr;//p[N][M]
    for(i = 0; i < N ;++i){
        for(j = 0; j < M;++j)
            printf("%d ", p[i][j]);
        printf("\n");
    }

   return 0;
}

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