首页 \ 问答 \ IBAction显示经度和纬度(快速)(IBAction to display latitude and longitude (swift))

IBAction显示经度和纬度(快速)(IBAction to display latitude and longitude (swift))

我有获取用户位置的代码。 我希望用户能够按下按钮并在屏幕上看到他们的坐标。 我该怎么做,因为我不能直接调用myLat或MyLong作为按钮功能,因为它是一个位置管理器功能。 为什么这个代码不工作?

 func locationManager(manager: CLLocationManager, didUpdateLocations locations: [CLLocation]) {

    // get most recient coordinate
    let myCoor = locations[locations.count - 1]

    //get lat & long
    var myLat = myCoor.coordinate.latitude
    let myLong = myCoor.coordinate.longitude
    let myCoor2D = CLLocationCoordinate2D(latitude: myLat, longitude: myLong)

    //set span
    let myLatDelta = 0.05
    let myLongDelta = 0.05
    let mySpan = MKCoordinateSpan(latitudeDelta: myLatDelta, longitudeDelta: myLongDelta)

    let myRegion = MKCoordinateRegion(center: myCoor2D, span: mySpan)
    self.LocationManager.stopUpdatingLocation()
 }




@IBAction func coo(sender: AnyObject) {
     self.coolat.text! = String(myLat)
     self.coolong.text! = String(myLong)
}

I have code that gets the users location. I want the user to be able to press a button and see their coordinates onscreen. how do I do this as I can't call myLat or MyLong for the button function directly as it is a location manager function. why isn't this code working?

 func locationManager(manager: CLLocationManager, didUpdateLocations locations: [CLLocation]) {

    // get most recient coordinate
    let myCoor = locations[locations.count - 1]

    //get lat & long
    var myLat = myCoor.coordinate.latitude
    let myLong = myCoor.coordinate.longitude
    let myCoor2D = CLLocationCoordinate2D(latitude: myLat, longitude: myLong)

    //set span
    let myLatDelta = 0.05
    let myLongDelta = 0.05
    let mySpan = MKCoordinateSpan(latitudeDelta: myLatDelta, longitudeDelta: myLongDelta)

    let myRegion = MKCoordinateRegion(center: myCoor2D, span: mySpan)
    self.LocationManager.stopUpdatingLocation()
 }




@IBAction func coo(sender: AnyObject) {
     self.coolat.text! = String(myLat)
     self.coolong.text! = String(myLong)
}

原文:https://stackoverflow.com/questions/40855440
更新时间:2024-03-14 18:03

最满意答案

类似的东西

public class SendPostRequest extends AsyncTask<String, Void, String> {

    private String passwd;
    public SendPostRequest(String pass) {
        super();
        this.passwd = pass;
    }

    protected void onPreExecute() {
    }

    protected String doInBackground(String... arg0) {

        try {

            URL url = new URL("https://www.domain.org/file.php"); // here is

            JSONObject postDataParams = new JSONObject();
            postDataParams.put("mensajeArea", passwd);
            Log.e("params", postDataParams.toString());

            HttpURLConnection conn = (HttpURLConnection) url.openConnection();
            conn.setReadTimeout(15000 /* milliseconds */);
            conn.setConnectTimeout(15000 /* milliseconds */);
            conn.setRequestMethod("POST");
            conn.setDoInput(true);
            conn.setDoOutput(true);

            OutputStream os = conn.getOutputStream();
            BufferedWriter writer = new BufferedWriter(
                    new OutputStreamWriter(os, "UTF-8"));
            writer.write(getPostDataString(postDataParams));

            writer.flush();
            writer.close();
            os.close();

            int responseCode = conn.getResponseCode();

            if (responseCode == HttpsURLConnection.HTTP_OK) {

                BufferedReader in = new BufferedReader(new
                        InputStreamReader(
                        conn.getInputStream()));

                StringBuffer sb = new StringBuffer("");
                String line = "";

                while ((line = in.readLine()) != null) {

                    sb.append(line);
                    break;
                }

                in.close();
                return sb.toString();

            } else {
                return new String("false : " + responseCode);
            }
        } catch (Exception e) {
            return new String("Exception: " + e.getMessage());
        }

    }
}

在构造函数的帮助下创建任务并设置passwd

在onclick中:

btnAdd1.setOnClickListener(new View.OnClickListener() {
    public void onClick(View v) {
        new SendPostRequest(passwd).execute();
        Toast.makeText(login.this, passwd, Toast.LENGTH_LONG).show();
        // btnAdd1 has been clicked
        alertD.dismiss();
    }
});

Something like that

public class SendPostRequest extends AsyncTask<String, Void, String> {

    private String passwd;
    public SendPostRequest(String pass) {
        super();
        this.passwd = pass;
    }

    protected void onPreExecute() {
    }

    protected String doInBackground(String... arg0) {

        try {

            URL url = new URL("https://www.domain.org/file.php"); // here is

            JSONObject postDataParams = new JSONObject();
            postDataParams.put("mensajeArea", passwd);
            Log.e("params", postDataParams.toString());

            HttpURLConnection conn = (HttpURLConnection) url.openConnection();
            conn.setReadTimeout(15000 /* milliseconds */);
            conn.setConnectTimeout(15000 /* milliseconds */);
            conn.setRequestMethod("POST");
            conn.setDoInput(true);
            conn.setDoOutput(true);

            OutputStream os = conn.getOutputStream();
            BufferedWriter writer = new BufferedWriter(
                    new OutputStreamWriter(os, "UTF-8"));
            writer.write(getPostDataString(postDataParams));

            writer.flush();
            writer.close();
            os.close();

            int responseCode = conn.getResponseCode();

            if (responseCode == HttpsURLConnection.HTTP_OK) {

                BufferedReader in = new BufferedReader(new
                        InputStreamReader(
                        conn.getInputStream()));

                StringBuffer sb = new StringBuffer("");
                String line = "";

                while ((line = in.readLine()) != null) {

                    sb.append(line);
                    break;
                }

                in.close();
                return sb.toString();

            } else {
                return new String("false : " + responseCode);
            }
        } catch (Exception e) {
            return new String("Exception: " + e.getMessage());
        }

    }
}

Create task with the help of constructor and set passwd

In onclick:

btnAdd1.setOnClickListener(new View.OnClickListener() {
    public void onClick(View v) {
        new SendPostRequest(passwd).execute();
        Toast.makeText(login.this, passwd, Toast.LENGTH_LONG).show();
        // btnAdd1 has been clicked
        alertD.dismiss();
    }
});

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