首页 \ 问答 \ 如何在SQL服务器上没有“WITH”或子查询的情况下简化此查询?(How can I simplify this query without “WITH” or Subquery on SQL server?)

如何在SQL服务器上没有“WITH”或子查询的情况下简化此查询?(How can I simplify this query without “WITH” or Subquery on SQL server?)

我有一个查询,可以在我的仓库和商店中筛选我的表格以查看积极的股票。

我只需要采取积极的价值,如果其中一个值是积极的,我只拿这个值。

WITH Resultat AS
(
    SELECT AR_Ref,StockDepots,StockStores,
        CASE 
         WHEN StockDepots > 0 AND StockStores > 0  THEN StockDepots + StockStores
         WHEN StockDepots > 0 THEN StockDepots
         WHEN StockStores > 0 THEN StockStores
         ELSE StockDepots + StockStores
        END AS StockMulti
    FROM ArticleStock 
)    
SELECT * FROM Resultat
WHERE StockMulti > 0
ORDER BY AR_Ref

小提琴: http : //rextester.com/RMSU6120

我的查询结果是好的,我需要知道如何不使用“WITH”或子查询来简化此查询?

编辑**

为什么我不需要WITH或SubQuery是因为我认为在这种情况下是过度杀伤性的,我认为可以在没有WITH或Subquery的情况下进行查询。


I've a query that filter my table for positive stock in my warehouse and stores.

I need to take only positive value and if one of values is positive I take this value only.

WITH Resultat AS
(
    SELECT AR_Ref,StockDepots,StockStores,
        CASE 
         WHEN StockDepots > 0 AND StockStores > 0  THEN StockDepots + StockStores
         WHEN StockDepots > 0 THEN StockDepots
         WHEN StockStores > 0 THEN StockStores
         ELSE StockDepots + StockStores
        END AS StockMulti
    FROM ArticleStock 
)    
SELECT * FROM Resultat
WHERE StockMulti > 0
ORDER BY AR_Ref

Fiddle : http://rextester.com/RMSU6120

My query result is Ok, I need to know How can I simplify this query without "WITH" or Subquery ?

EDIT**

Why I don't need WITH or SubQuery is because I think is overkill in this case and I think it's possible to make this query without WITH or Subquery.


原文:https://stackoverflow.com/questions/43778165
更新时间:2022-02-21 08:02

最满意答案

如您所知,要将两个数字一起添加,您可以使用+函数:

(+ 2 1)
;;=> 3

要将两个向量一起添加,可以使用mapv函数将两个向量压缩在一起,使用+

(mapv + [1 0] [1 0])
;;=> [2 0]

要在矢量序列中执行此矢量添加的左边折叠,可以使用reduce

(reduce #(mapv + %1 %2) [[0 0] [1 0] [1 0] [1 0]])
;;=> [3 0]

或者,用partial的用法替换该函数文字:

(reduce (partial mapv +) [[0 0] [1 0] [1 0] [1 0]])
;;=> [3 0]

要获得这个左边折叠的所有中间步骤,可以使用reductions

(reductions (partial mapv +) [[0 0] [1 0] [1 0] [1 0]])
;;=> ([0 0] [1 0] [2 0] [3 0])

最后,要仅返回此序列中的唯一元素,可以使用set

(set (reductions (partial mapv +) [[0 0] [1 0] [1 0] [1 0]]))
;;=> #{[0 0] [1 0] [3 0] [2 0]}

To add two numbers together, you can use the + function, as you know:

(+ 2 1)
;;=> 3

To add two vectors together, you can use the mapv function to zip together the two vectors using +:

(mapv + [1 0] [1 0])
;;=> [2 0]

To perform a left fold of this vector addition across a sequence of vectors, you can use reduce:

(reduce #(mapv + %1 %2) [[0 0] [1 0] [1 0] [1 0]])
;;=> [3 0]

Or, replacing that function literal with a usage of partial:

(reduce (partial mapv +) [[0 0] [1 0] [1 0] [1 0]])
;;=> [3 0]

To obtain all the intermediate steps of this left fold, you can use reductions:

(reductions (partial mapv +) [[0 0] [1 0] [1 0] [1 0]])
;;=> ([0 0] [1 0] [2 0] [3 0])

Finally, to return only the unique elements from this sequence, you can use set:

(set (reductions (partial mapv +) [[0 0] [1 0] [1 0] [1 0]]))
;;=> #{[0 0] [1 0] [3 0] [2 0]}

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