首页 \ 问答 \ 如何在scala中的对象内使用方法?(how to use method inside an object in scala?)

如何在scala中的对象内使用方法?(how to use method inside an object in scala?)

我在scala工作表中有这个示例代码。 我不明白为什么我无法访问代码底部的函数。

object chapter5 {
  println("Welcome to the Scala worksheet")

  trait Stream2[+A] {
    def uncons: Option[(A, Stream2[A])]
    def isEmpty: Boolean = uncons.isEmpty
  }
  object Stream2 {

    def empty[A]: Stream2[A] =
      new Stream2[A] { def uncons = None }

    def cons[A](hd: => A, tl: => Stream2[A]): Stream2[A] =
      new Stream2[A] {
        lazy val uncons = Some((hd, tl))
      }

    def  apply[A](as: A*): Stream2[A] =
      if (as.isEmpty) empty
      else cons(as.head, apply(as.tail: _*))
  }

  val s = Stream2(1, 2, 3, 4, 5, 6, 7, 8, 9, 10)
    s.isEmpty //I can access to the function declared in the trait
    s.cons // error  // I can not access to the function declared in the object
}

另外我需要编写toList方法。 我应该在哪里写呢? 如果我无法访问这些方法,我该如何测试呢?


I have this sample code in a scala worksheet. I do not understand why I can not access to the functions as at the bottom of the code.

object chapter5 {
  println("Welcome to the Scala worksheet")

  trait Stream2[+A] {
    def uncons: Option[(A, Stream2[A])]
    def isEmpty: Boolean = uncons.isEmpty
  }
  object Stream2 {

    def empty[A]: Stream2[A] =
      new Stream2[A] { def uncons = None }

    def cons[A](hd: => A, tl: => Stream2[A]): Stream2[A] =
      new Stream2[A] {
        lazy val uncons = Some((hd, tl))
      }

    def  apply[A](as: A*): Stream2[A] =
      if (as.isEmpty) empty
      else cons(as.head, apply(as.tail: _*))
  }

  val s = Stream2(1, 2, 3, 4, 5, 6, 7, 8, 9, 10)
    s.isEmpty //I can access to the function declared in the trait
    s.cons // error  // I can not access to the function declared in the object
}

In addition I need to write the toList method. Where should I write it? How can I test it if I can not access to the methods ?


原文:https://stackoverflow.com/questions/28860279
更新时间:2023-02-09 12:02

最满意答案

您需要调用[cell.detailTextLabel sizeToFit]以使标签在cellForRowAtIndexPath中实际调整大小。 它不会因为您将numberOfLines设置为0而自行调整大小。请参阅此问题并阅读其答案以获得更多说明。


Turns out I just needed to enable all of the Autosizing options in interface builder for the label.

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