如何在php中查找非空值并显示if条件[复制](How to find the not null values in php and display in if condition [duplicate])

 
 
 这个问题在这里已经有了答案： 
 
 
 
  
 如何检查数组是否包含空元素？ 5个答案 
 
 
 
 
 在这里我有一个数组，我想找到不空值和显示在前端，假设在这个数组中的所有键值在null意味着我想显示所有值为null，假设任何一个键不为null意味着我想显示什么是价值 
 
<?php
$array = array('a' => '','b' => 'Kani' , 'c' => '', 'd' => 'Raja');

 if (in_array(null, $array)) {

     echo "There are null values.";
 }else{
  echo "Not Null";
 }
?>
 
 
 
 这里关键a和d不为空，所以我想要像Kani和Raja这样的关键值 
 

 
 
This question already has an answer here:
 
 
 
  
 How to check if an array contains empty elements?  5 answers  
 
 
 
 
Here i have one array in that array i want to find not null values and display in frond end ,suppose in this array all key values in null means i want to display all values are null,suppose any one of the key is not null means i want to display what is that value
 
<?php
$array = array('a' => '','b' => 'Kani' , 'c' => '', 'd' => 'Raja');

 if (in_array(null, $array)) {

     echo "There are null values.";
 }else{
  echo "Not Null";
 }
?>
 
 
 
Here key a and d is not null so i want take this key value like Kani and Raja
 

原文：https://stackoverflow.com/questions/42256037