获得一周的反应(Get the week correspoding to a day)
我想让一周对应一个日期。 例如,如果我放置2012年12月24日,我想从太阳获得一周:坐下来,本周应该包含dec24。
我尝试了几个代码。 目前我正在使用此代码
public static String[] getpreviousweek(int num) { // TODO Auto-generated method stub Calendar c = Calendar.getInstance(); // Set the calendar to monday of the current week c.set(Calendar.DAY_OF_WEEK, Calendar.SUNDAY); c.add(Calendar.DATE, num * 7); // Print dates of the current week starting on Monday SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd", Locale.ENGLISH); String[] days = new String[7]; for (int i = 0; i < 7; i++) { days[i] = df.format(c.getTime()); c.add(Calendar.DAY_OF_MONTH, 1); } return days; }
I am trying to get the week corresponding to a date. For example if I placed 2012 dec: 24 I want to get the week from sun: to sat and this week should contain dec24.
I tried several codes. Currently I am using this code
public static String[] getpreviousweek(int num) { // TODO Auto-generated method stub Calendar c = Calendar.getInstance(); // Set the calendar to monday of the current week c.set(Calendar.DAY_OF_WEEK, Calendar.SUNDAY); c.add(Calendar.DATE, num * 7); // Print dates of the current week starting on Monday SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd", Locale.ENGLISH); String[] days = new String[7]; for (int i = 0; i < 7; i++) { days[i] = df.format(c.getTime()); c.add(Calendar.DAY_OF_MONTH, 1); } return days; }
原文:https://stackoverflow.com/questions/33080831
更新时间:2024-01-11 17:01
最满意答案
这是一种简单有效的方法:
var orderedRooms = rooms .OrderBy(room => !room.People.Any(person => person.IsLead)) // room with lead will be first .GroupBy(room => room.RoomType) // RoomType with lead will be first .SelectMany(group => group); // flatten the list of groups into one list
此查询符合以下要求:
- 有序列表中的第一个房间是潜在客户所在的房间。
- 所有相同类型的房间都互相依赖。
但是,它不按字母顺序对房间类型进行排序。
Here's a simple, efficient approach:
var orderedRooms = rooms .OrderBy(room => !room.People.Any(person => person.IsLead)) // room with lead will be first .GroupBy(room => room.RoomType) // RoomType with lead will be first .SelectMany(group => group); // flatten the list of groups into one list
This query meets the following requirements:
- The first room in the ordered list is the one that the lead is in.
- All rooms of the same type follow each other.
However, it does not sort the room types alphabetically.
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选择一些列来强制要素: cols <- c("A", "C", "D", "H") 使用lapply()来强制并替换选定的列: data[cols] <- lapply(data[cols], factor) 检查结果: sapply(data, class) # A B C D E F G # "factor" "integer" "factor" "factor" "integer" ...
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我已经更新了你的jsfiddle ,它应该按照预期的方式工作。 HTML:
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