首页 \ 问答 \ 使用相同的“规则”检查多个变量(Checking multiple variables with the same “rules”)

使用相同的“规则”检查多个变量(Checking multiple variables with the same “rules”)

我必须构建一个对象数组。 我可以“长手”,但我希望找到一种方法来遍历一些变量,并检查每个变量,将它们“推”到数组中的正确位置。

我有这个:

//this is the starting array...I'm going to update these objects
    operationTime = [ 
{"isActive":false,"timeFrom":null,"timeTill":null},//Monday which is operationTime[0]
{"isActive":false,"timeFrom":null,"timeTill":null},
{"isActive":false,"timeFrom":null,"timeTill":null},
{"isActive":false,"timeFrom":null,"timeTill":null},
{"isActive":false,"timeFrom":null,"timeTill":null},
{"isActive":false,"timeFrom":null,"timeTill":null},
{"isActive":false,"timeFrom":null,"timeTill":null}
];

//I get the below via an API call
var monHours = placeHours.mon_open_close;
var tueHours = placeHours.tue_open_close;
var wedHours = placeHours.wed_open_close;
var thuHours = placeHours.thu_open_close;
var friHours = placeHours.fri_open_close;
var satHours = placeHours.sat_open_close;
var sunHours = placeHours.sun_open_close;
var sunHours = placeHours.sun_open_close;


//here's where I'm stuck. 
if (monHours.length>0){ 
   var arr = monHours[0].split("-");
    operationTime[0].isActive= true;
    operationTime[0].timeFrom= arr[0];
    operationTime[0].timeTill= arr[1];  
}
else {
    operationTime[0].isActive= false;
}

我的if/else在上面使用星期一的例子中完美地工作,但我不想在一周中的七天内写这个让它不必要的复杂。 我怎么能把这个压缩成一个单独的“函数”来测试每个变量并将它推入数组对象的正确位置?


I have to construct an array of objects. I can do it "long hand," but I'm hoping to find a way to iterate through some variables and check each at "push" them into the right spot in the array.

I have this:

//this is the starting array...I'm going to update these objects
    operationTime = [ 
{"isActive":false,"timeFrom":null,"timeTill":null},//Monday which is operationTime[0]
{"isActive":false,"timeFrom":null,"timeTill":null},
{"isActive":false,"timeFrom":null,"timeTill":null},
{"isActive":false,"timeFrom":null,"timeTill":null},
{"isActive":false,"timeFrom":null,"timeTill":null},
{"isActive":false,"timeFrom":null,"timeTill":null},
{"isActive":false,"timeFrom":null,"timeTill":null}
];

//I get the below via an API call
var monHours = placeHours.mon_open_close;
var tueHours = placeHours.tue_open_close;
var wedHours = placeHours.wed_open_close;
var thuHours = placeHours.thu_open_close;
var friHours = placeHours.fri_open_close;
var satHours = placeHours.sat_open_close;
var sunHours = placeHours.sun_open_close;
var sunHours = placeHours.sun_open_close;


//here's where I'm stuck. 
if (monHours.length>0){ 
   var arr = monHours[0].split("-");
    operationTime[0].isActive= true;
    operationTime[0].timeFrom= arr[0];
    operationTime[0].timeTill= arr[1];  
}
else {
    operationTime[0].isActive= false;
}

My if/else works perfectly in the above example using Monday, but I don't want to write this for seven days of the week making it unnecessarily complicated. How could I condense this into a single "function" that'll test each variable and push it into the array object in the correct position?


原文:https://stackoverflow.com/questions/45449805
更新时间:2023-09-15 20:09

最满意答案

使用data.table连接:

replacement = data.table(a = char, new_a = num, key = "a")

dt.fixed = replacement[dt][, a := ifelse(is.na(new_a), a, new_a)][, new_a := NULL]

Use data.table joins:

replacement = data.table(a = char, new_a = num, key = "a")

dt.fixed = replacement[dt][, a := ifelse(is.na(new_a), a, new_a)][, new_a := NULL]

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