发送查看网站隐藏内容所需的数据(Sending data needed to see hidden content from website)

 最近我试图让app关注一个特定的网站。 我需要访问记录后具有可见内容的页面。 如果我明白，下面的代码显示，首先我需要连接到url1以避免默认主页，所以在这里我无法发送数据（登录，密码）。 我需要从url3看到一个内容，但在这里我也无法发送数据，因为没有登录和密码字段。 他们在url2。 我尝试了本网站的其他解决方案，但我只收到每个人都可以看到的内容。 有人可以帮忙吗？ 
 
private class Parser extends AsyncTask<Void, Void, Void> {
    String h;
    String url1 = "http://www.klt.net.pl/";
    String url2 = "http://www.klt.net.pl/index.php?a=logowanie";
    String url3 = "http://www.klt.net.pl/index.php?a=przedmecz1&b=2&d=2038";

    @Override
    protected void onPreExecute() {
        super.onPreExecute();
        pd = new ProgressDialog(MainActivity.this);
        pd.setTitle("Parser");
        pd.setMessage("Loading...");
        pd.setIndeterminate(false);
        pd.show();
    }

    @Override
    protected Void doInBackground(Void... params) {
        try {
            Connection.Response response = Jsoup.connect(url1)
            .method(Connection.Method.GET)
            .timeout(50000)
            .followRedirects(true)
            .execute();
        Document document = Jsoup.connect(url2)
            .cookies(response.cookies())
            .get();

        } catch (IOException e) {
            e.printStackTrace();
        }
        return null;
    }

    @Override
    protected void onPostExecute(Void result) {
        pd.dismiss();
    }
}
 
 编辑： 
 
@Override
protected Void doInBackground(Void... params) {
    try {
        Connection.Response response = Jsoup.connect(url1)
        .method(Connection.Method.GET)
        .timeout(50000)
        .followRedirects(true)
        .execute();

        Connection.Response loginRes = Jsoup.connect(url2)
        .userAgent("Mozilla/5.0 (Macintosh; Intel Mac OS X 10_10_5) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/44.0.2403.157 Safari/537.36")
        .data("login", getlog2,
        "haslo", getpass2)
        .cookies(response.cookies()) 
        .method(Method.POST)
        .execute();

        Map<String, String> cookies = new Map<String, String>();
        cookies.addAll(loginRes.cookies());

        Connection.Response otherRes = Jsoup.connect(url3)
        .cookies(cookies)
        .method(Method.POST)
        .execute();

        d3 = Jsoup.connect(url3)
        .cookies(otherRes.cookies())
        .get();
 
 我的更新代码。 这可以吗？ 我在Map中有错误（无法实例化类型且无法解析类型）。 

Recently I am trying to make app concerns a specific website. I need to have access to page which has visible content after logging. If I understand, below code shows that firstly I need to connect to url1 to avoid default mainpage so here I cannot send data (login, password). I need to see a content from url3, but here I cannot send data also because there is no login and password field. They are in url2. I tried other solutions from this website, but I receive only content that is visible for everyone. Can anybody help?
 
private class Parser extends AsyncTask<Void, Void, Void> {
    String h;
    String url1 = "http://www.klt.net.pl/";
    String url2 = "http://www.klt.net.pl/index.php?a=logowanie";
    String url3 = "http://www.klt.net.pl/index.php?a=przedmecz1&b=2&d=2038";

    @Override
    protected void onPreExecute() {
        super.onPreExecute();
        pd = new ProgressDialog(MainActivity.this);
        pd.setTitle("Parser");
        pd.setMessage("Loading...");
        pd.setIndeterminate(false);
        pd.show();
    }

    @Override
    protected Void doInBackground(Void... params) {
        try {
            Connection.Response response = Jsoup.connect(url1)
            .method(Connection.Method.GET)
            .timeout(50000)
            .followRedirects(true)
            .execute();
        Document document = Jsoup.connect(url2)
            .cookies(response.cookies())
            .get();

        } catch (IOException e) {
            e.printStackTrace();
        }
        return null;
    }

    @Override
    protected void onPostExecute(Void result) {
        pd.dismiss();
    }
}
 
EDIT:
 
@Override
protected Void doInBackground(Void... params) {
    try {
        Connection.Response response = Jsoup.connect(url1)
        .method(Connection.Method.GET)
        .timeout(50000)
        .followRedirects(true)
        .execute();

        Connection.Response loginRes = Jsoup.connect(url2)
        .userAgent("Mozilla/5.0 (Macintosh; Intel Mac OS X 10_10_5) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/44.0.2403.157 Safari/537.36")
        .data("login", getlog2,
        "haslo", getpass2)
        .cookies(response.cookies()) 
        .method(Method.POST)
        .execute();

        Map<String, String> cookies = new Map<String, String>();
        cookies.addAll(loginRes.cookies());

        Connection.Response otherRes = Jsoup.connect(url3)
        .cookies(cookies)
        .method(Method.POST)
        .execute();

        d3 = Jsoup.connect(url3)
        .cookies(otherRes.cookies())
        .get();
 
My updated code. Is that ok? I have error in Map (cannot instatiate the type and cannot resolved type).

原文：https://stackoverflow.com/questions/32790438