首页 \ 问答 \ 如何分析java线程转储？(How to analyze a java thread dump?)

如何分析java线程转储？(How to analyze a java thread dump?)

 我正在尝试更多地了解java，特别是关于内存管理和线程。 为此，我最近有兴趣看看线程转储。 
 

 以下是使用VisualVM的Web应用程序的几行，这是一个内置的java工具： 
 

"Finalizer" daemon prio=8 tid=0x02b3d000 nid=0x898 in Object.wait() [0x02d0f000]
   java.lang.Thread.State: WAITING (on object monitor)
    at java.lang.Object.wait(Native Method)
    - waiting on <0x27ef0288> (a java.lang.ref.ReferenceQueue$Lock)
    at java.lang.ref.ReferenceQueue.remove(ReferenceQueue.java:118)
    - locked <0x27ef0288> (a java.lang.ref.ReferenceQueue$Lock)
    at java.lang.ref.ReferenceQueue.remove(ReferenceQueue.java:134)
    at java.lang.ref.Finalizer$FinalizerThread.run(Finalizer.java:159)

   Locked ownable synchronizers:
    - None

"Reference Handler" daemon prio=10 tid=0x02b3b800 nid=0x494 in Object.wait() [0x02cbf000]
   java.lang.Thread.State: WAITING (on object monitor)
    at java.lang.Object.wait(Native Method)
    - waiting on <0x27ef0310> (a java.lang.ref.Reference$Lock)
    at java.lang.Object.wait(Object.java:485)
    at java.lang.ref.Reference$ReferenceHandler.run(Reference.java:116)
    - locked <0x27ef0310> (a java.lang.ref.Reference$Lock)

 

 首先我有一些变量名称的问题： 
 

     
 
  •  tid和nid是什么意思？ 
    •  
 
  •  Object.wait之后的圆括号中的数字是多少？ 
    •  

 

 然后对于堆栈跟踪本身： 
 

     
 
  •  什么意思等于<.....>（一个java.lang ....） ，什么是<..>中的数字 
    •  
 
  •  这是什么意思锁定<.....>（一个java.lang ....）同样的问题，什么在<..> 
    •  

 

 我以为这个词被锁在一个等待状态，但是我错了。 其实我想知道为什么锁定重复三次，但线程处于可运行状态，如同样的转储中所示： 
 

"Thread-0" prio=6 tid=0x02ee3800 nid=0xc1c runnable [0x03eaf000]
   java.lang.Thread.State: RUNNABLE
    at java.io.FileInputStream.readBytes(Native Method)
    at java.io.FileInputStream.read(FileInputStream.java:199)
    at java.io.BufferedInputStream.read1(BufferedInputStream.java:256)
    at java.io.BufferedInputStream.read(BufferedInputStream.java:317)
    - locked <0x23963378> (a java.io.BufferedInputStream)
    at sun.nio.cs.StreamDecoder.readBytes(StreamDecoder.java:264)
    at sun.nio.cs.StreamDecoder.implRead(StreamDecoder.java:306)
    at sun.nio.cs.StreamDecoder.read(StreamDecoder.java:158)
    - locked <0x23968450> (a java.io.InputStreamReader)
    at java.io.InputStreamReader.read(InputStreamReader.java:167)
    at java.io.BufferedReader.fill(BufferedReader.java:136)
    at java.io.BufferedReader.readLine(BufferedReader.java:299)
    - locked <0x23968450> (a java.io.InputStreamReader)
    at java.io.BufferedReader.readLine(BufferedReader.java:362)
    at org.codehaus.plexus.util.cli.StreamPumper.run(StreamPumper.java:145)

 

 最后，这是最糟糕的： 
 

"CompilerThread0" daemon prio=10 tid=0x02b81000 nid=0x698 waiting on condition [0x00000000]
   java.lang.Thread.State: RUNNABLE

 

 该线程处于可运行状态，但正在等待状态。 什么条件和什么是0x00000？ 
 

 为什么堆栈跟踪很短，没有任何线程类的证据？ 
 

 如果你能回答我所有的问题，我将非常感激。 
 

 谢谢 

I am trying to understand more about java, especially about memory management and threads. For this reason I have recently found interest in looking at thread dumps.
 

Here are few lines taken from a web app using VisualVM, a built-in tool for java:
 

"Finalizer" daemon prio=8 tid=0x02b3d000 nid=0x898 in Object.wait() [0x02d0f000]
   java.lang.Thread.State: WAITING (on object monitor)
    at java.lang.Object.wait(Native Method)
    - waiting on <0x27ef0288> (a java.lang.ref.ReferenceQueue$Lock)
    at java.lang.ref.ReferenceQueue.remove(ReferenceQueue.java:118)
    - locked <0x27ef0288> (a java.lang.ref.ReferenceQueue$Lock)
    at java.lang.ref.ReferenceQueue.remove(ReferenceQueue.java:134)
    at java.lang.ref.Finalizer$FinalizerThread.run(Finalizer.java:159)

   Locked ownable synchronizers:
    - None

"Reference Handler" daemon prio=10 tid=0x02b3b800 nid=0x494 in Object.wait() [0x02cbf000]
   java.lang.Thread.State: WAITING (on object monitor)
    at java.lang.Object.wait(Native Method)
    - waiting on <0x27ef0310> (a java.lang.ref.Reference$Lock)
    at java.lang.Object.wait(Object.java:485)
    at java.lang.ref.Reference$ReferenceHandler.run(Reference.java:116)
    - locked <0x27ef0310> (a java.lang.ref.Reference$Lock)

 

First I have questions about some variable names: 
 

     
 
  • what does tid and nid mean? 
    •  
 
  • What is the figure in squared parenthesis after Object.wait?
    •  

 

Then for the stack trace itself:
 

     
 
  • what does it mean waiting on <.....> (a java.lang....) and what's the number in <..>
    •  
 
  • what does it mean locked <.....> (a java.lang....) same question, what's in <..>
    •  

 

I thought that the word locked was related in someway to a wait condition, however, I was wrong. In fact, I am wondering why locked is repeated three times, but the thread is in runnable state as seen in the same dump:
 

"Thread-0" prio=6 tid=0x02ee3800 nid=0xc1c runnable [0x03eaf000]
   java.lang.Thread.State: RUNNABLE
    at java.io.FileInputStream.readBytes(Native Method)
    at java.io.FileInputStream.read(FileInputStream.java:199)
    at java.io.BufferedInputStream.read1(BufferedInputStream.java:256)
    at java.io.BufferedInputStream.read(BufferedInputStream.java:317)
    - locked <0x23963378> (a java.io.BufferedInputStream)
    at sun.nio.cs.StreamDecoder.readBytes(StreamDecoder.java:264)
    at sun.nio.cs.StreamDecoder.implRead(StreamDecoder.java:306)
    at sun.nio.cs.StreamDecoder.read(StreamDecoder.java:158)
    - locked <0x23968450> (a java.io.InputStreamReader)
    at java.io.InputStreamReader.read(InputStreamReader.java:167)
    at java.io.BufferedReader.fill(BufferedReader.java:136)
    at java.io.BufferedReader.readLine(BufferedReader.java:299)
    - locked <0x23968450> (a java.io.InputStreamReader)
    at java.io.BufferedReader.readLine(BufferedReader.java:362)
    at org.codehaus.plexus.util.cli.StreamPumper.run(StreamPumper.java:145)

 

Then last of all, this was the worst of them:
 

"CompilerThread0" daemon prio=10 tid=0x02b81000 nid=0x698 waiting on condition [0x00000000]
   java.lang.Thread.State: RUNNABLE

 

This thread is in runnable state, but it's waiting on condition. What condition and what is 0x00000?
 

Why the stack trace is so short without any evidence of the thread class?
 

If you could answer to all my questions I would be very grateful.
 

Thanks

原文：https://stackoverflow.com/questions/7599608
更新时间：2022-01-06 20:01

最满意答案

 如何这样的事情： 
 

WebDataSource *dataSource = [[sourceSignatureWebView mainFrame] dataSource];

WebArchive *archive = [[WebArchive alloc]
                       initWithMainResource:[dataSource mainResource]
                       subresources:nil
                       subframeArchives:nil];

[[archive data] writeToURL…

 

 或者，你是否真的在HTML文件而不是网络存档之后？ 

How about something like this:
 

WebDataSource *dataSource = [[sourceSignatureWebView mainFrame] dataSource];

WebArchive *archive = [[WebArchive alloc]
                       initWithMainResource:[dataSource mainResource]
                       subresources:nil
                       subframeArchives:nil];

[[archive data] writeToURL…

 

Or are you actually after an HTML file rather than web archive?

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