首页 \ 问答 \ 在二维数组中填入主对角线(Filling in the main diagonals in a 2D array)

在二维数组中填入主对角线(Filling in the main diagonals in a 2D array)

我试图编写一个代码来填充NxN矩阵中的2个主要对角线,例如:如果N = 5(通过命令行输入),我们将有一个填充0的5x5矩阵,对角线将有2s填入,如:

2 0 0 0 2
0 2 0 2 0
0 0 2 0 0
0 2 0 2 0
2 0 0 0 2

我写了一个全零表的代码,但是我不知道如何填写对角线。 看看5x5的情况,我将不得不填写以下指数的矩阵:

#1 (0,0)  (0,n-1) 
#2 (1,1) (1,n-2)
#3 (2,2) (2,n-3) 
#4 (3,1) (3, n-2)
#5 (4,0) (4,n-1)

但是,由于N可以是任意数字,我假设首先我必须找到中间行,之后我必须以相反的顺序递减索引。

我只学了2周的Java,而这个很难。 我的代码为零填充表是这样的:

public static void main (String[] args){
        int n = Integer.parseInt(args[0]);
        System.out.println(n);
        int[][] table = new int[n][]; 
         for (int i = 0; i < n; i++) { 
         table[i] = new int[i + 1]; 
         for (int j = 0; j <= i; j++) { 
         table[i][j] = (0); 


            }
        } System.out.print(Arrays.deepToString(table));
    }

显然,这与我所需要达到的目标相去甚远,我不确定它是否完全正确。 我真的很感谢一些帮助。


I am trying to write a code that fills in the 2 main diagonals in an NxN matrix, for example: if N=5 (which is entered through command line), we would have a 5x5 matrix filled with zeros and the diagonals would have 2s filled in, like:

2 0 0 0 2
0 2 0 2 0
0 0 2 0 0
0 2 0 2 0
2 0 0 0 2

I wrote a code for an all-zero table, but i can't figure our how to fill in the diagonals. Looking at the case of 5x5 i would have to fill in the matrix at the following indices:

#1 (0,0)  (0,n-1) 
#2 (1,1) (1,n-2)
#3 (2,2) (2,n-3) 
#4 (3,1) (3, n-2)
#5 (4,0) (4,n-1)

However, since N can be any number, i assume that first i have to find the middle row, after which i have to decrement the indices in the reverse order.

I am learning Java for 2 weeks only and this one is pretty hard. My code for a zero-filled table is this:

public static void main (String[] args){
        int n = Integer.parseInt(args[0]);
        System.out.println(n);
        int[][] table = new int[n][]; 
         for (int i = 0; i < n; i++) { 
         table[i] = new int[i + 1]; 
         for (int j = 0; j <= i; j++) { 
         table[i][j] = (0); 


            }
        } System.out.print(Arrays.deepToString(table));
    }

Obviously, this is very far from what i need to achieve, and i am not sure if it's entirely right. I would really appreciate some help.


原文:https://stackoverflow.com/questions/22204140
更新时间:2022-04-03 19:04

最满意答案

简答:不,你不能。

使用交换不是应用程序所做的事情:操作系统的内存管理系统负责这一点。

如果您需要在进程中一次加载超过2GB的数据(而不是根据需要从每个块的磁盘检索数据),那么您就会遇到严重的设计问题。


编辑 :由于您已经在使用64位操作系统,请确保您正在为x64平台(或AnyCPU)编译应用程序,并且您的应用程序未使用WOW64作为32位进程运行。


Short answer: no you can't.

Using the swap is not something applications do: the memory management system of the operating system is responsible of that.

If you need to load more than 2GB of data in your process in one time (and not retrieve data from disk per chunks as necessary), then you have a serious design problem.


EDIT: As you're already using a 64-bit OS, make sure you're compiling your application for x64 platforms (or AnyCPU) and your application is not running as a 32-bit process using WOW64.

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