首页 \ 问答 \ Ember.js将params对象传递给linkTo或action helper(Ember.js pass params object to linkTo or action helper)

Ember.js将params对象传递给linkTo或action helper(Ember.js pass params object to linkTo or action helper)

有没有办法将params对象传递给linTo或action helper?

我有一个对象,它需要复合键。 我正在使用Ember Model并且必须修改适配器。 在获取初始对象的路由器中,我使用必要的密钥传递一个params对象。 当使用linkTo或者使用transitionToRoute时,我的问题是尝试做同样的事情。 据我所知,两者都没有再次击中路由器。

我回到这个问题。 我仍然不确定处理这个问题的正确方法。

App.Router.map(function () {
  this.resource("clients", { path: 'clients' }, function () {
    this.resource("client", { path: ':client_id' }, function () {
      this.resource("claims", function () {
        this.resource('claim', { path: ':claim_id/:claim_sub' }, function () {
          this.resource('lines', { path: 'lines' }, function () {
            this.resource('line', { path: ':line_id' }, function () {
              this.resource('flags', function () {
                this.resource('flag', { path: ':flag_id' });
              });
            });
            this.route('claim_lines');
          });
         });
       });
     });
  });
  this.route("errors", { path: '/errors/:error_id' });
});

当我链接到索赔下的任何内容时,复合slu are,我将那些设置为未定义。

UPDATE

序列化正是我所需要的。

App.ClaimRoute = Nucleus.Route.extend({
  model: function (params) {
    params.client_id = this.modelFor('client').get('client_id');
    return App.Claim.find('claim', params);
  },

  serialize: function (model) {
    return { claim_id: model.get('cla_seq'), claim_sub: model.get('cla_sub') };
  }
});

Is there a way to pass a params object to a linTo or action helper?

I have an object and it needs compound keys. I am using Ember Model and had to modify the adapter. In the Router that gets the initial object i pass a params object with the necessary keys. My problem is trying to do the same thing when using either a linkTo or action with a transitionToRoute. Neither hit the router again as far as I can tell.

Im coming back to this questions. Im still not sure the proper way to handle this.

App.Router.map(function () {
  this.resource("clients", { path: 'clients' }, function () {
    this.resource("client", { path: ':client_id' }, function () {
      this.resource("claims", function () {
        this.resource('claim', { path: ':claim_id/:claim_sub' }, function () {
          this.resource('lines', { path: 'lines' }, function () {
            this.resource('line', { path: ':line_id' }, function () {
              this.resource('flags', function () {
                this.resource('flag', { path: ':flag_id' });
              });
            });
            this.route('claim_lines');
          });
         });
       });
     });
  });
  this.route("errors", { path: '/errors/:error_id' });
});

When i link to anything under the claim, where the compound slugs are, i get those set to undefined.

UPDATE

The serialize was just what i needed.

App.ClaimRoute = Nucleus.Route.extend({
  model: function (params) {
    params.client_id = this.modelFor('client').get('client_id');
    return App.Claim.find('claim', params);
  },

  serialize: function (model) {
    return { claim_id: model.get('cla_seq'), claim_sub: model.get('cla_sub') };
  }
});

原文:https://stackoverflow.com/questions/16723397
更新时间:2022-09-20 18:09

最满意答案

您需要处理不同类型的TypeSyntax es。 请参见: http//source.roslyn.io/#Microsoft.CodeAnalysis.CSharp/Syntax/TypeSyntax.cs,29171ac4ad60a546,references

您在调试器中看到的是SimpleNameSyntax ,它具有公共Identifier属性。

更新

var ns = objectCreationExpressionSyntax.Type as NameSyntax;
if (ns != null)
{
  return ns.Identifier.ToString();
}

var pts = objectCreationExpressionSyntax.Type as PredefinedTypeSyntax;
if (pts != null)
{
  return pts.Keyword.ToString();
}

... 

所有其他子类型都需要交付。 请注意, ArrayType.ElementType也是一个TypeSyntax ,因此您很可能需要使此方法递归。


You'll need to handle the different types of TypeSyntaxes. See here: http://source.roslyn.io/#Microsoft.CodeAnalysis.CSharp/Syntax/TypeSyntax.cs,29171ac4ad60a546,references

What you see in the debugger is a SimpleNameSyntax, which does have a public Identifier property.

Update

var ns = objectCreationExpressionSyntax.Type as NameSyntax;
if (ns != null)
{
  return ns.Identifier.ToString();
}

var pts = objectCreationExpressionSyntax.Type as PredefinedTypeSyntax;
if (pts != null)
{
  return pts.Keyword.ToString();
}

... 

All other subtypes would need to be handed. Note that ArrayType.ElementType is also a TypeSyntax, so you would most probably need to make this method recursive.

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