动态代理在JavaScript？(Dynamic proxies in javascript?)

 始终注意编译器的警告。 如果您没有收到任何警告，请检查您的编译器设置。 
 
$ gcc -Wall -O a.c
a.c: In function ‘main’:
a.c:6:5: warning: implicit declaration of function ‘malloc’ [-Wimplicit-function-declaration]
     list_nums = malloc(argc * sizeof(int));
     ^
a.c:6:17: warning: incompatible implicit declaration of built-in function ‘malloc’
     list_nums = malloc(argc * sizeof(int));
                 ^
a.c:8:24: warning: assignment makes integer from pointer without a cast
         list_nums[i-1] = argv[i];
                        ^
 
 第一个警告说没有声明malloc ; 你错过了#include <stdlib.h> 。 在大多数系统中，这不会导致实际问题。 第二个警告是同样问题的结果。 
 
 第三个警告表明存在问题。 argv是一个指向char的指针数组，因此argv[i]是指向char的指针。 list_nums指向一个整数数组。 所以你要指定一个整数的指针。 您打印出来的随机数字是内存中参数的地址。 
 
 您可以将字符串数组复制到字符串数组中。 在这种情况下，您需要将list_nums更改为char*数组，并使用%s说明符进行打印。 
 
 看来你打算将参数解释为整数。 如果要将参数（即字符串）转换为整数，则需要明确地执行此操作。 您可以使用atoi函数快速一次性代码，或strtol使用健壮的代码（ atoi不允许错误检查）。 
 
long *list_nums = malloc((argc-1) * sizeof(*list_nums));
char *end;
if (list_nums == NULL) {
    fprintf(stderr, "Not enough memory\n");
    return EXIT_FAILURE;
}
for (i = 1; i < argc; i++) {
    list_nums[i-1] = strtol(argv[i], &end, 0);
    if (*end != 0) {
        fprintf(stderr, "Invalid argument: %s\n", argv[i]);
        return EXIT_FAILURE;
    }
}
for (i = 0; i < argc-1; i++) {
    printf("%ld, ", list_nums[i]);
}

Always pay attention to your compiler's warnings. If you aren't getting any warnings, check your compiler settings.
 
$ gcc -Wall -O a.c
a.c: In function ‘main’:
a.c:6:5: warning: implicit declaration of function ‘malloc’ [-Wimplicit-function-declaration]
     list_nums = malloc(argc * sizeof(int));
     ^
a.c:6:17: warning: incompatible implicit declaration of built-in function ‘malloc’
     list_nums = malloc(argc * sizeof(int));
                 ^
a.c:8:24: warning: assignment makes integer from pointer without a cast
         list_nums[i-1] = argv[i];
                        ^
 
The first warning says that malloc isn't declared; you're missing #include <stdlib.h>. On most systems this won't cause an actual problem. The second warning is a consequence of the same problem.
 
The third warning indicates a real problem. argv is an array of pointers to char, so argv[i] is a pointer to char. list_nums points to an array of integers. So you're assigning a pointer to an integer. The random-looking numbers that you're printing out are the addresses of the arguments in memory.
 
You can copy an array of strings into an array of strings. In this case, you need to change list_nums to an array of char*, and use the %s specifier for printing.
 
It seems that you intended to interpret the arguments as integers though. If you want to convert the arguments — which are strings — to integers, you need to do that explicitly. You can use the atoi function for quick throwaway code, or strtol for robust code (atoi doesn't permit error checking).
 
long *list_nums = malloc((argc-1) * sizeof(*list_nums));
char *end;
if (list_nums == NULL) {
    fprintf(stderr, "Not enough memory\n");
    return EXIT_FAILURE;
}
for (i = 1; i < argc; i++) {
    list_nums[i-1] = strtol(argv[i], &end, 0);
    if (*end != 0) {
        fprintf(stderr, "Invalid argument: %s\n", argv[i]);
        return EXIT_FAILURE;
    }
}
for (i = 0; i < argc-1; i++) {
    printf("%ld, ", list_nums[i]);
}