需要Docker引擎群模式的服务发现(Need for service discovery for docker engine swarm mode)

 您可以通过单个XPath表达式选择所需的内容，如此转换所示： 
 
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:template match="sourceElement">
     <xsl:copy-of select=
     "document('file:///c:/temp/delete/dept.xml')
               /*/*[child1 = current()]
                     /*[not(self::child1)]
     "/>
 </xsl:template>
</xsl:stylesheet>
 
 当此转换应用于提供的XML文档时： 
 
<sourceRoot>
 <sourceElement>foo</sourceElement>
</sourceRoot>
 
 第二个提供的XML文档驻留在c:\temp\delete\dept.xml的本地文件系统中： 
 
<departments>
 <department>
  <child1>bar</child1>
  <child2>bar2</child2>
  <child3>bar3</child3>
 </department>
 <department>
  <child1>baz</child1>
  <child2>baz2</child2>
  <child3>baz3</child3>
 </department>
 <department>
  <child1>foo</child1>
  <child2>foo2</child2>
  <child3>foo3</child3>
 </department>
</departments>
 
 产生了想要的正确结果： 
 
<child2>foo2</child2>
<child3>foo3</child3>
 
 更新 ： 
 
 如果我们想要更改上面所选元素的名称，这非常简单： 
 
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:template match="sourceElement">
     <xsl:apply-templates select=
     "document('file:///c:/temp/delete/dept.xml')
               /*/*[child1 = current()]
                     /*[not(self::child1)]
     "/>
 </xsl:template>

 <xsl:template match="*[starts-with(name(), 'child')]">
  <xsl:element name="{name()}value"><xsl:value-of select="."/></xsl:element>
 </xsl:template>
</xsl:stylesheet>
 
 产生 ： 
 
<child2value>foo2</child2value>
<child3value>foo3</child3value>

What you want can be selected by a single XPath expression, as demonstrated with this transformation:
 
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:template match="sourceElement">
     <xsl:copy-of select=
     "document('file:///c:/temp/delete/dept.xml')
               /*/*[child1 = current()]
                     /*[not(self::child1)]
     "/>
 </xsl:template>
</xsl:stylesheet>
 
when this transformation is applied on the provided XML document:
 
<sourceRoot>
 <sourceElement>foo</sourceElement>
</sourceRoot>
 
and the second provided XML document resides in the local file system at c:\temp\delete\dept.xml:
 
<departments>
 <department>
  <child1>bar</child1>
  <child2>bar2</child2>
  <child3>bar3</child3>
 </department>
 <department>
  <child1>baz</child1>
  <child2>baz2</child2>
  <child3>baz3</child3>
 </department>
 <department>
  <child1>foo</child1>
  <child2>foo2</child2>
  <child3>foo3</child3>
 </department>
</departments>
 
the wanted, correct result is produced:
 
<child2>foo2</child2>
<child3>foo3</child3>
 
Update:
 
If we want to change the names of the selected elements above, this is really simple:
 
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:template match="sourceElement">
     <xsl:apply-templates select=
     "document('file:///c:/temp/delete/dept.xml')
               /*/*[child1 = current()]
                     /*[not(self::child1)]
     "/>
 </xsl:template>

 <xsl:template match="*[starts-with(name(), 'child')]">
  <xsl:element name="{name()}value"><xsl:value-of select="."/></xsl:element>
 </xsl:template>
</xsl:stylesheet>
 
produces:
 
<child2value>foo2</child2value>
<child3value>foo3</child3value>