打印连续数字(Printing consecutive numbers)

 我已经对整数数组{1,2,3,7,9,24,25,26,78}进行了排序，并希望连续打印以打印{1-3,7,9,24-26,78}。 也就是说，每次在阵列中出现一组连续数字时，我想打印出从最小数字到最大数字的范围。 
 
import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Consecutive{

public static void main(String[] args){
    int[] a={1,2,3,7,9,24,25,26,78};

    for(int i=0;i<a.length;i++){
        int count=0;
        int first=0;

    /*  System.out.println(i);*/
        first=a[i];

        if(a[i+1]-a[i]==1){

            count++;

            int last=a[i]+count;
            i++;
            System.out.println(first + " " + last);

                }else{


                System.out.println(a[i]);

                }

    }
}
}

I have sorted integer array {1,2,3,7,9,24,25,26,78} and would like to print consecutive to print {1-3,7,9,24-26,78}. That is, every time there is a set of consecutive numbers occurring in the array, I would like to print out the range from the minimum number to the maximum number.
 
import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Consecutive{

public static void main(String[] args){
    int[] a={1,2,3,7,9,24,25,26,78};

    for(int i=0;i<a.length;i++){
        int count=0;
        int first=0;

    /*  System.out.println(i);*/
        first=a[i];

        if(a[i+1]-a[i]==1){

            count++;

            int last=a[i]+count;
            i++;
            System.out.println(first + " " + last);

                }else{


                System.out.println(a[i]);

                }

    }
}
}

原文：https://stackoverflow.com/questions/36963019