带有可选参数的c ++函数(c++ function with optional arguments)

 声明这样的方法的最佳方法是什么： 
 
calc( string name, string arguments, 
      string lib, 
      string &output, string &error, 
      string finishInfo )
 
 每个参数都是可选的？ 如果需要，用户可以传递名称，参数和错误; 只传递finishInfo或传递所有六个参数。 可能是最友好的用户可以打电话： 
 
calc( "my name", , "my library", , , );
 
 但我不知道是否有可能没有提升。 我不能超载，因为我需要创建62种方法。 我最好的想法是： 
 
calc( string * name = NULL, string * arguments = NULL, 
      string * lib = NULL, 
      string * output = NULL, string * error = NULL, 
      string * finishInfo = NULL )
 
 我将所有内容都改为指针，这样我们就需要调用 
 
calc( ptr_myName, NULL, ptr_myLib, NULL, NULL, NULL );
 
 要么 
 
calc( string name = "", string arguments = "",
      string lib = "",
...
calc( "", "",
      "my library",

What is the best way to declare a method like this:
 
calc( string name, string arguments, 
      string lib, 
      string &output, string &error, 
      string finishInfo )
 
where every parameter is optional? User can pass name, arguments and error if needed; pass only finishInfo or pass all six arguments. Probably the most user friendly is being able to call:
 
calc( "my name", , "my library", , , );
 
but I don't know if it's possible to do without boost. I cannot overload, because I'd need to create 62 methods. My best idea is:
 
calc( string * name = NULL, string * arguments = NULL, 
      string * lib = NULL, 
      string * output = NULL, string * error = NULL, 
      string * finishInfo = NULL )
 
I'm changing everything to pointers, this way we need to call
 
calc( ptr_myName, NULL, ptr_myLib, NULL, NULL, NULL );
 
or
 
calc( string name = "", string arguments = "",
      string lib = "",
...
calc( "", "",
      "my library",

原文：https://stackoverflow.com/questions/41833458