C ++中的静态变量(Static variables in C++)
我想知道一个头文件中静态变量与一个类中声明的区别是什么。 当在头文件中声明静态变量时,其范围限制为.h文件或跨所有单位。 一般静态变量在.cpp文件中被初始化,在类中声明时呢? 那么这意味着静态可变范围限于2个编译单元?
I would like to know what is the difference between static variables in a header file vs declared in a class. When static variable is declared in a header file is its scope limited to .h file or across all units. Also generally static variable is initialized in .cpp file when declared in a class right? So that does mean static variable scope is limited to 2 compilation units?
原文:https://stackoverflow.com/questions/3698043
更新时间:2022-03-12 13:03
最满意答案
您可以使用
awk
来实现这一点,awk ' NR==FNR{ if(a[$1]=="") a[$1]=$2; next} /[0-9]/{ if(a[$1]==$2){ print $0,"match" } else { print $0,"mismatch" } id=$1 }' File1 File2
输出:
2 13 match 2 13 match 3 13 match 3 3 mismatch 5 14 match 5 15 mismatch
简要说明,
NR==FNR{...}
:在File1中,如果id以前从未显示过,则将id / value保存到数组a
if(a[$1]==$2)
:如果id和值在File2中匹配,则将记录视为匹配,否则不匹配。You may use
awk
to achieve that,awk ' NR==FNR{ if(a[$1]=="") a[$1]=$2; next} /[0-9]/{ if(a[$1]==$2){ print $0,"match" } else { print $0,"mismatch" } id=$1 }' File1 File2
Output:
2 13 match 2 13 match 3 13 match 3 3 mismatch 5 14 match 5 15 mismatch
Brief explanation,
NR==FNR{...}
: in File1, save id/value to arraya
if the id has never shown previouslyif(a[$1]==$2)
: if the id and value match in File2, view the record as match, and mismatch otherwise.
相关问答
更多-
简短定义: grep :搜索文件中的特定术语 #usage $ grep This file.txt Every line containing "This" Every line containing "This" Every line containing "This" Every line containing "This" $ cat file.txt Every line containing "This" Every line containing "This" Every line cont ...
-
拥有源文件: $ cat it.dat Babbo Natale I maiali non volano Il figlio del padre Elfo $ cat en.dat Santa Claus Pigs don't fly The son of the father Elf 这个awk : awk 'NR==FNR{if(NF>3){a[NR]}else{a[NR]=1;print > "filtered_it.dat"}} NR!=FNR && a[FNR]{print > ...
-
您可以使用awk来实现这一点, awk ' NR==FNR{ if(a[$1]=="") a[$1]=$2; next} /[0-9]/{ if(a[$1]==$2){ print $0,"match" } else { print $0,"mismatch" } id=$1 }' File1 File2 输出: 2 13 match 2 13 match 3 13 match 3 3 mismatch 5 14 match 5 15 mismatc ...
-
Awk,tail,sed或其他 - 对于大文件哪个更快?(Awk, tail, sed or others - which one faster for big files?)[2024-04-12]
tail和head是特别为此目的而创建的工具,所以直观的想法是它们对它进行了相当优化。 另一方面, awk和sed完全可以做到这一点,因为它们就像是一把瑞士军刀 ,但这不应该是对他们拥有的多个其他人的最佳“技能”。 使用awk,sed或其他方法从大型文件打印行的高效方法? 有一个很好的比较方法和head / tail被视为最好的方法。 因此,我会去tail + head 。 还要注意的是,如果它不仅是最后一行,而且它们是文本中的最后一行,在awk (或sed )中,您可以选择在最后一行之后exit 。 这样 ... -
$ awk '{ for (i=1;i$ cat tst.awk BEGIN { tgt = "./." } NR==FNR { for (i=1;i<=NF;i++) { if ($i == tgt) { hit[FNR,i]=1 } } next } { for (i=1;i<=NF;i++) { if ( hit[FNR,i] ) { $i = tgt } } print } $ ...不要使用uniq的-d标志。 这将只显示重复的行。 来自uniq --help : -d, --repeated only print duplicate lines, one for each group 相反,请不要使用uniq参数: sort *.txt | uniq | ... 或者更简单地说, sort可以为你独立: sort -u *.txt | ... Don't use the -d flag of uniq. That will show only the duplic ...
使用awk,“if”,然后sed(Using awk, “if”, then sed)[2023-08-18]
Awk的强大功能可以让你传递变量,并使用gsub()函数创建sed部分: awk -v UM="$UM" -v UM_lower="$UM_lower" -v num="$num" '{ if (NR > num && NR < num_max && $1 == UM) { gsub(UM, UM_lower) } print $0 }' The power of Awk lets you pass variables and make the sed part with the gsub() funct ...如何使用sed或awk将两个文件的每一行结合在一起?(How to combine each line of two files together using sed or awk?)[2022-10-15]
与您的输出不同的顺序,但可能有用: awk ' FNR == NR { words[ $1 ] = 1; next } FNR < NR { if ( length( $1 ) <= 6 ) for ( word in words ) { print word $0 } } ' fileA fileB 输出: coolsnake sadsnake beanssnake coolbread sadbrea ...awk '{if(NR%5==1) { getline line < "FILEA"; print line; } else { print $0; }}' FILEB 如果你想使用文件名作为参数,你也可以试试这个: awk 'NR!=FNR{exit} {if(NR%5==1) { getline line < ARGV[2]; print line; } else { print $0; }}' FILEB FILEA awk '{if(NR%5==1) { getline line < "FILE ...相关文章
更多- 《C/C++图像处理编程》扫描版[PDF]
- 谁给推荐一个C++的JSON库
- C++ Hadoop实战备忘
- 《轻松学C++编程》扫描版[PDF]
- java server怎样和c++ client实现SSL通信??
- 《从零开始学Visual C++》扫描版[PDF]
- 《上海交大C++面向对象》[RMVB]
- 《数据结构(C++版)(第2版)》扫描版[PDF]
- 《新版 Visual C++全能速查宝典》扫描版[PDF]
- 【Hadoop学习】在伪分布式Hadoop上实践word count程序——C/C++ Pipes版本
最新问答
更多- 您如何使用git diff文件,并将其应用于同一存储库的副本的本地分支?(How do you take a git diff file, and apply it to a local branch that is a copy of the same repository?)
- 将长浮点值剪切为2个小数点并复制到字符数组(Cut Long Float Value to 2 decimal points and copy to Character Array)
- OctoberCMS侧边栏不呈现(OctoberCMS Sidebar not rendering)
- 页面加载后对象是否有资格进行垃圾回收?(Are objects eligible for garbage collection after the page loads?)
- codeigniter中的语言不能按预期工作(language in codeigniter doesn' t work as expected)
- 在计算机拍照在哪里进入
- 使用cin.get()从c ++中的输入流中丢弃不需要的字符(Using cin.get() to discard unwanted characters from the input stream in c++)
- No for循环将在for循环中运行。(No for loop will run inside for loop. Testing for primes)
- 单页应用程序:页面重新加载(Single Page Application: page reload)
- 在循环中选择具有相似模式的列名称(Selecting Column Name With Similar Pattern in a Loop)
- System.StackOverflow错误(System.StackOverflow error)
- KnockoutJS未在嵌套模板上应用beforeRemove和afterAdd(KnockoutJS not applying beforeRemove and afterAdd on nested templates)
- 散列包括方法和/或嵌套属性(Hash include methods and/or nested attributes)
- android - 如何避免使用Samsung RFS文件系统延迟/冻结?(android - how to avoid lag/freezes with Samsung RFS filesystem?)
- TensorFlow:基于索引列表创建新张量(TensorFlow: Create a new tensor based on list of indices)
- 企业安全培训的各项内容
- 错误:RPC失败;(error: RPC failed; curl transfer closed with outstanding read data remaining)
- C#类名中允许哪些字符?(What characters are allowed in C# class name?)
- NumPy:将int64值存储在np.array中并使用dtype float64并将其转换回整数是否安全?(NumPy: Is it safe to store an int64 value in an np.array with dtype float64 and later convert it back to integer?)
- 注销后如何隐藏导航portlet?(How to hide navigation portlet after logout?)
- 将多个行和可变行移动到列(moving multiple and variable rows to columns)
- 提交表单时忽略基础href,而不使用Javascript(ignore base href when submitting form, without using Javascript)
- 对setOnInfoWindowClickListener的意图(Intent on setOnInfoWindowClickListener)
- Angular $资源不会改变方法(Angular $resource doesn't change method)
- 在Angular 5中不是一个函数(is not a function in Angular 5)
- 如何配置Composite C1以将.m和桌面作为同一站点提供服务(How to configure Composite C1 to serve .m and desktop as the same site)
- 不适用:悬停在悬停时:在元素之前[复制](Don't apply :hover when hovering on :before element [duplicate])
- 常见的python rpc和cli接口(Common python rpc and cli interface)
- Mysql DB单个字段匹配多个其他字段(Mysql DB single field matching to multiple other fields)
- 产品页面上的Magento Up出售对齐问题(Magento Up sell alignment issue on the products page)