首页 \ 问答 \ 错误:(34)在'com.hackerinside.jaisonjoseph.radioplanet'包中找不到属性'srcCompat'的资源标识符(Error:(34) No resource identifier found for attribute 'srcCompat' in package 'com.hackerinside.jaisonjoseph.radioplanet')

错误:(34)在'com.hackerinside.jaisonjoseph.radioplanet'包中找不到属性'srcCompat'的资源标识符(Error:(34) No resource identifier found for attribute 'srcCompat' in package 'com.hackerinside.jaisonjoseph.radioplanet')

当我向卡片视图添加图像时,我发现错误如错误:(34)找不到包'com.hackerinside.jaisonjoseph.radioplanet'中属性'srcCompat'的资源标识符

这是我的content_main.xml

<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto"
xmlns:tools="http://schemas.android.com/tools"
android:id="@+id/Relative"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:background="@android:color/holo_blue_dark"

app:layout_behavior="@string/appbar_scrolling_view_behavior"
tools:context="com.hackerinside.jaisonjoseph.radioplanet.MainActivity"
tools:showIn="@layout/activity_main">


<Button
    android:text="Button"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:id="@+id/button"
    android:layout_centerVertical="true"
    android:layout_centerHorizontal="true" />

<android.support.v7.widget.CardView
    android:layout_width="350dp"
    android:layout_height="200dp"
    app:cardElevation="10dp"
    android:id="@+id/card"
    android:layout_above="@+id/button"
    android:layout_centerHorizontal="true"
    android:layout_marginBottom="15dp"
    android:layout_marginTop="20dp">


    <ImageView
        android:layout_width="match_parent"
        android:layout_height="match_parent"
        app:srcCompat="@mipmap/ic_launcher"
        android:id="@+id/imageView" />
</android.support.v7.widget.CardView>


when i add an image to the card view i am geting error like Error:(34) No resource identifier found for attribute 'srcCompat' in package 'com.hackerinside.jaisonjoseph.radioplanet'

this is my content_main.xml

<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto"
xmlns:tools="http://schemas.android.com/tools"
android:id="@+id/Relative"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:background="@android:color/holo_blue_dark"

app:layout_behavior="@string/appbar_scrolling_view_behavior"
tools:context="com.hackerinside.jaisonjoseph.radioplanet.MainActivity"
tools:showIn="@layout/activity_main">


<Button
    android:text="Button"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:id="@+id/button"
    android:layout_centerVertical="true"
    android:layout_centerHorizontal="true" />

<android.support.v7.widget.CardView
    android:layout_width="350dp"
    android:layout_height="200dp"
    app:cardElevation="10dp"
    android:id="@+id/card"
    android:layout_above="@+id/button"
    android:layout_centerHorizontal="true"
    android:layout_marginBottom="15dp"
    android:layout_marginTop="20dp">


    <ImageView
        android:layout_width="match_parent"
        android:layout_height="match_parent"
        app:srcCompat="@mipmap/ic_launcher"
        android:id="@+id/imageView" />
</android.support.v7.widget.CardView>


原文:
更新时间:2022-04-13 10:04

最满意答案

特定

list1 = [[objid:1, name:"One"], [objid:2, name:"Two"]]
list2 = [[objid:2, name:"Hello"]]

为了获得list1条目,其中匹配来自list2的objids的条目被过滤掉,将需要减去的id收集到一个集合中,然后构造一个谓词,测试给定对象的id是否不在该集合中:

ids = list2.collect { it['objid'] } as Set
list3 = list1.findAll { !ids.contains(it['objid']) }

(使用一个集合而不是一个列表应该使查找更快。)

结果是list3包含:

[[objid:1, name:One]]

Given

list1 = [[objid:1, name:"One"], [objid:2, name:"Two"]]
list2 = [[objid:2, name:"Hello"]]

In order to get list1 entries with entries matching objids from list2 filtered out, collect the ids that need to be subtracted into a set, then construct a predicate that tests that the id of the given object isn't in that set:

ids = list2.collect { it['objid'] } as Set
list3 = list1.findAll { !ids.contains(it['objid']) }

(Using a set instead of a list should make the lookups faster.)

The result is that list3 contains:

[[objid:1, name:One]]

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