如果没有Codeigniter路由(Codeigniter routing if not)

 我想配置像这样的codeigniter路由 
 
 这很好用 
 
$route['login/(:any)']  = "login/index/$1";
$route['profile/(:any)']  = "profile/index/$1";
 
 但我想这样做，如果不是=登录或个人资料，那么我想这样做 
 
$route['not(login or profile)']          = "home/index/$1";
 
 这段代码不对，请帮我给我代码。 
 
 我有3个控制器他们是1.家2.配置文件3.登录 
 
 现在如果我使用这个domain.com/profile然后我想运行配置文件控制器，如果我去domain.com/profile/john我需要从我的控制器domain.com/profile/john/edit我得到这个名字john还需要从控制器获取此john并进行编辑 。 
 
 现在，如果我顺其自然 
 
domain.com/login
 
 然后我想运行配置文件控制器，如果我去 
 
domain.com/login/best
 
 我需要从我的控制器中获得最佳名称 
 
domain.com/login/best/sure
 
 我还需要从控制器那里得到最好的和最好的 。 
 
 如果我一起去 
 
domain.com/
or domain.com/bestoffer
or domain.com/others
or domain.com/blabla
 
 没有配置文件和登录域后的任何事情我需要运行家庭控制器 
 
 就这样 

I want to configure codeigniter routing something like this
 
This is working good
 
$route['login/(:any)']  = "login/index/$1";
$route['profile/(:any)']  = "profile/index/$1";
 
But i want to do this if not = login or profile then i want to do this
 
$route['not(login or profile)']          = "home/index/$1";
 
This code is not right so please help me by give me code for this.
 
i have 3 controller they are 1. home 2. profile 3. login
 
Now if i go with this domain.com/profile then i want run profile controller, and if i go with domain.com/profile/john i need go get this name john from my controller domain.com/profile/john/edit i also need to get this john and edit from controller.
 
Now if i go with this
 
domain.com/login
 
then i want run profile controller, and if i go with
 
domain.com/login/best
 
i need go get this name best from my controller
 
domain.com/login/best/sure
 
i also need to get this best and sure from controller.
 
And if i go with
 
domain.com/
or domain.com/bestoffer
or domain.com/others
or domain.com/blabla
 
anything after domain without profile and login i need to run Home controller
 
That's all

原文：https://stackoverflow.com/questions/40282639