codeigniter form_dropdown返回错误的值(codeigniter form_dropdown return wrong value)

 我的模特， 
 
function get_partners_name()
{
    $q = $this->db->select("id,fname,lname")
                      ->from('partner');
    $all_partners = $q->get()->result();
    $data = array();
    foreach($all_partners as $partner)
    {
       $data[$partner->id] = $partner->fname.' '.$partner->lname;
    }
    return $data;
}
 
 我的控制器var_dump（$ partners）数据是， 
 
array (size=2)
  38 => string 'Mahesh' (length=6)
  40 => string 'Rahul' (length=4)
 
 我的看法， 
 
<?php array_unshift($partners, "-Select-");?>
<?php echo form_dropdown('parnter', $partners,'',''); ?>
 
 所以在下拉列表中我要显示， 
 
<option value='0'>-Select-</option>
<option value='38'>Mahesh</option>
<option value='40'>Rahul</option>
 
 但它显示， 
 
<option value='0'>-Select-</option>
<option value='1'>Mahesh</option>
<option value='2'>Rahul</option>

My Model,
 
function get_partners_name()
{
    $q = $this->db->select("id,fname,lname")
                      ->from('partner');
    $all_partners = $q->get()->result();
    $data = array();
    foreach($all_partners as $partner)
    {
       $data[$partner->id] = $partner->fname.' '.$partner->lname;
    }
    return $data;
}
 
my controller var_dump($partners) data is,
 
array (size=2)
  38 => string 'Mahesh' (length=6)
  40 => string 'Rahul' (length=4)
 
My view,
 
<?php array_unshift($partners, "-Select-");?>
<?php echo form_dropdown('parnter', $partners,'',''); ?>
 
so in dropdown i want to display,
 
<option value='0'>-Select-</option>
<option value='38'>Mahesh</option>
<option value='40'>Rahul</option>
 
But it display,
 
<option value='0'>-Select-</option>
<option value='1'>Mahesh</option>
<option value='2'>Rahul</option>

原文：https://stackoverflow.com/questions/21520720