C句柄 - 如何使用它们?(C Handles - How to work with them?)
我在Dreamweaver的插件的一些文档中有我说的如下:
void ** connectionData
•connectionData参数是代理在调用其他API函数时希望Dreamweaver传递给它的数据的句柄。
关于connectionData,我手册中没有其他信息。 从字面上思考,我认为句柄指的是通用句柄,但是我无法找到有关使用C语言的通用句柄的文档。
HANDLE h = connectionData;
在我的代码中编译。 我究竟如何获得此数据结构中的“秘密”/有人可以解释C的通用句柄是如何工作的?
I have in some documentation for a plugin for Dreamweaver I am making that says the following:
void **connectionData
• The connectionData argument is a handle to the data that the agent wants Dreamweaver to pass to it when calling other API functions.
I have no other information than this from the manual in regard to connectionData. Thinking literally, I figured handle refered to a generic handle,however I am not able to find documentation on working with generic handles in regard to C.
HANDLE h = connectionData;
Does compile in my code. How exactly do I get the "secrets" inside this data structure/can someone explain how generic handles for C work?
原文:https://stackoverflow.com/questions/3311669
最满意答案
当你找到你的第一个奇数时,你可以直接返回。
public boolean hasUneven(int[] a) { for (int i = 0; i < a.length; i++) { if (a[i] % 2 != 0) { return true; } } return false; }
you can directy return when you find your first odd number.
public boolean hasUneven(int[] a) { for (int i = 0; i < a.length; i++) { if (a[i] % 2 != 0) { return true; } } return false; }
相关问答
更多-
下列中不属于面向对象的编程语言的是?[2022-05-30]
a -
使用for循环创建一个方法来查找奇数丰富的sigma函数数(Creating a method with a for loop to find odd abundant sigma function numbers)[2021-08-15]
这是一个愚蠢的问题; 从Sigma函数中删除print语句。 public static int Sigma(int s){ int a = 0; for(int i=1;i<=s;i++){ if(s%i==0) a = a + i; } System.out.print(a); //why do you have it here? return a; } The silly problem it was; remove ... -
在数组中交换奇数和偶数(Swap odd and even numbers in array)[2022-09-16]
好吧,如果你想要奇数是第一个,用%2==0替换任何%2!=0 ,用%2!=0替换任何%2==0 %2!=0 : public static int[] seperator(int[] arr1, int left, int right){ int temp; if(left>=right) return arr1; else if(arr1[left]%2==0 && arr1[right]%2!=0){ temp=arr1[left]; ... -
将您的&&更改为|| 它应该工作: if (height%3 != 0 || height%2 != 1) { errorFlag(grid); } 为了进一步确认,我只用12个伪随机数测试了精确的代码 - 添加了控制台输出语句 - 这就是我得到的结果: 3 is bad 4 is good 5 is good 6 is good 33 is bad 27 is bad 56 is good 24 is good 15 is bad 45 is bad 46 is good 78 is g ...
-
如何创建一个方法来检查数组中是否有奇数?(How to make a method that checks if there is an odd number in an array?)[2022-03-28]
当你找到你的第一个奇数时,你可以直接返回。 public boolean hasUneven(int[] a) { for (int i = 0; i < a.length; i++) { if (a[i] % 2 != 0) { return true; } } return false; } you can directy return when you find your first odd number. public ... -
要从数组中获取奇数和偶数,您只需对数组使用for循环,并在每次将数字奇数添加到奇数数组时进行验证,否则,将其添加到偶数数组,并计算同一时间每个数组的总和: var array:Array = [5,44,30,96,9,95,51,14,38,64,57,86,64,48,31,11,89,51,24,4]; var odds:Array = [], evens:Array = [], odds_sum:int = 0, evens_sum:int = 0 ; for(var i ...
-
使用GUI在Array中的偶数元素和奇数元素之间进行交替(Alternating between even and odd elements in Array with GUI)[2022-02-13]
删除for for-loop ,它阻止事件调度线程处理repaint请求 相反,每次调用actionPerformed方法时,更新某种计数器,然后对其采取行动,例如...... this.timer = new Timer(100, new ActionListener() { private int sequence = 0; public void actionPerformed(ActionEvent evt) { if (sequence % 2 == 0) { ... -
尝试查找数组中唯一的奇数或偶数时出现未知错误(Unknown error when trying to find the only odd or even number in an array)[2024-02-04]
很可能你的问题在于宣布你的evens和odds列表。 当你调用evens.add(integers[i]); ,evens本身没有宣布。 你的片段中缺少这篇文章,但我猜你有以下内容: Listevens; 在调用方法之前实例化它将解决NullPointerException 。 您无法在从未实例化的对象上调用方法。 List evens = new ArrayList<>(); Most likely your problem is at the declarati ... -
一个简单的方法: #include
int absdiffevenoddpopcount(uint64_t x) { uint64_t a = x & 0x5555555555555555; uint64_t b = x & ~0x5555555555555555; while(a && b) { a &= a - 1; b &= b - 1; } x = a ? a : b; int r = 0; ... -
奇数甚至是线(odd and even to line)[2022-07-02]
array_chunk($array, 2); http://php.net/manual/en/function.array-chunk.php array_chunk($array, 2); http://php.net/manual/en/function.array-chunk.php