拆分包含问号和等号的字符串的最佳方法(Best way to split a string containing question marks and equals)

 有一个我有一个java字符串的问题： 
 
String aString="name==p==?header=hello?aname=?????lname=lastname";
 
 我需要在问号上分开，然后是等号。 
 
 结果应该是键/值对： 
 
name = "=p=="
header = "hello"
aname = "????"
lname = "lastname"
 
 问题是aname和lname成为： 
 
name = ""
lname = "????lname=lastname"
 
 我的代码只是通过执行aString.split("\\?",2)来拆分 
 它将返回2个字符串。一个包含键/值对，第二个字符串包含字符串的其余部分。 如果我在字符串中找到一个问号，我会对第二个字符串进行递归以进一步分解。 
 
private String split(String aString)
 {
    System.out.println("Split: " + aString);
    String[] vals = aString.split("\\?",2);
    System.out.println("  - Found: " + vals.length);
    for ( int c = 0;c<vals.length;c++ )
       {
        System.out.println("  - "+ c + "| String: [" + vals[c] + "]" );
        if(vals[c].indexOf("?") > 0 )
          {
            split(vals[c]);
           }
        }
    return ""; // For now return nothing...
 }
 
 任何想法我怎么可以允许一个名字？ 
 免责声明：是的，我的正则表达式技能非常低，所以我不知道是否可以通过正则表达式来完成。 

Having an issue where I have a java string:
 
String aString="name==p==?header=hello?aname=?????lname=lastname";
 
I need to split on question marks followed by equals.
 
The result should be key/value pairs:
 
name = "=p=="
header = "hello"
aname = "????"
lname = "lastname"
 
The problem is aname and lname become:
 
name = ""
lname = "????lname=lastname"
 
My code simply splits by doing aString.split("\\?",2)
 which will return 2 strings.One contains a key/value pair and the second string contains the rest of the string. If I find a question mark in the string, I recurse on the second string to further break it down.
 
private String split(String aString)
 {
    System.out.println("Split: " + aString);
    String[] vals = aString.split("\\?",2);
    System.out.println("  - Found: " + vals.length);
    for ( int c = 0;c<vals.length;c++ )
       {
        System.out.println("  - "+ c + "| String: [" + vals[c] + "]" );
        if(vals[c].indexOf("?") > 0 )
          {
            split(vals[c]);
           }
        }
    return ""; // For now return nothing...
 }
 
Any ideas how I could allow a name of ?
 Disclaimer: Yes , My Regex skills are very low, so I don't know if this could be done via a regex expression.

原文：https://stackoverflow.com/questions/23695951