首页 \ 问答 \ 通过存储在pair中的键查找std :: set中的键(Finding key in std::set by key stored in pair)

通过存储在pair中的键查找std :: set中的键(Finding key in std::set by key stored in pair)

 所以我对c ++很新，我对如何在我的集合上实现find()函数有点困惑，该函数存储了pair项目。 我已经阅读了如何插入和删除它们对的项目但是对任何解释如何使用find （或其他一些方法，如果有的话）的任何人来说，通过该对的第一项找到一个值。  
set<pair<string, CustomObject>> *items = new set<pair<string, CustomObject>>();
 
 然后让我说我在集合中插入几对然后我想通过搜索存储为该对中的第一项的“密钥”来找到其中一对。 我认为这将涉及在该对上调用.first但我只是遇到麻烦。 这是我试图实现的基本功能  
bool inSet(string key){
    return this->items->find(pair<string, CustomObject>(key, null).first)
}
 
 我能够在地图对象中实现一切正常，但之后我不得不切换到一个集合，因为我希望能够对数据结构中的项目进行排序，并且我被告知您无法在地图中有效地执行此操作，因此集合。 

So i'm fairly new to c++ and i'm a little confused on how to implement the find() function on my set which is storing a pair item. Ive read on how to insert and remove items by their pair but came up dry on anyone explaining how to use find (Or some other method, if there is one) to find a value by the first item of the pair. 
set<pair<string, CustomObject>> *items = new set<pair<string, CustomObject>>();
 
Then lets say I insert a few pairs into the set then I want to find one of those pair by searching for the "key" being stored as the first item in the pair. I think it would involve calling the .first on the pair but im just having trouble with that. This is the basic function im trying to implement 
bool inSet(string key){
    return this->items->find(pair<string, CustomObject>(key, null).first)
}
 
I was able to implement everything just fine in a map object but then I had to switch to a set because I wanted to be able to sort the items in the data structure and I was told that you cant efficiently do this in a map, hence the set.

原文：https://stackoverflow.com/questions/35818787

更新时间：2022-03-17 20:03

最满意答案

 试一试。  
 这应该修复显示问题，同时保留500秒淡入。  
 当快速移动鼠标时它基本上清除了显示内容，因此你不会得到凌乱的过渡。  
$(document).ready(function() {
var flag = 1;
var liLength = $(".slideMenu ul li").length;
var num = 1;
var numHover;
var numTmp=0;
$(".slideMenuCont .item").fadeOut(0);
$(".slideMenuCont .item:eq(0)").fadeIn(500);            
var myInterval = function(){
    interval = setInterval(function(){
        if(num>=liLength)
            num=0;
        $(".slideMenu ul li").removeClass("active");
        $(".slideMenu ul li:eq("+num+")").addClass("active");
        $(".slideMenuCont .item").fadeOut(500);
        $(".slideMenuCont .item:eq("+num+")").fadeIn(500);
        num++;
    },3000);
}
var stop = function(){
    clearInterval(interval);
}
$(".slideMenu ul li").on({
    mouseenter: function () {
        stop();
        $(".slideMenu ul li").removeClass("active");
        if(num>=1)
            numTmp=num-1;
        else numTmp=num;
        numHover=$(".slideMenu ul li").index(this); 
        num=numHover;
        if(numHover!=numTmp){
            $(".slideMenuCont .item").fadeOut(0);
            $(".slideMenuCont .item").stop().fadeOut(500); 
            $(".slideMenuCont .item").css("display","none");
            $(this).addClass("active");
             $(".slideMenuCont .item:eq("+num+")").fadeIn(500);
        }
    },
    mouseleave: function () {
        if(num<liLength)
            num++;
        myInterval();
    }
});
var Auto = function(){
    myInterval();
}
Auto();
 
 }）;  
 更新：尝试合并两个$（“。slideMenuCont .item”）。stop（）。fadeOut（500）; 和$（“。slideMenuCont .item”）。css（“display”，“none”）; 

give this a try. 
This should fix the display Issue while preserving the 500 sec fade in. 
It basically clears the display contents when moving the mouse fast so you dont get the messy transitions. 
$(document).ready(function() {
var flag = 1;
var liLength = $(".slideMenu ul li").length;
var num = 1;
var numHover;
var numTmp=0;
$(".slideMenuCont .item").fadeOut(0);
$(".slideMenuCont .item:eq(0)").fadeIn(500);            
var myInterval = function(){
    interval = setInterval(function(){
        if(num>=liLength)
            num=0;
        $(".slideMenu ul li").removeClass("active");
        $(".slideMenu ul li:eq("+num+")").addClass("active");
        $(".slideMenuCont .item").fadeOut(500);
        $(".slideMenuCont .item:eq("+num+")").fadeIn(500);
        num++;
    },3000);
}
var stop = function(){
    clearInterval(interval);
}
$(".slideMenu ul li").on({
    mouseenter: function () {
        stop();
        $(".slideMenu ul li").removeClass("active");
        if(num>=1)
            numTmp=num-1;
        else numTmp=num;
        numHover=$(".slideMenu ul li").index(this); 
        num=numHover;
        if(numHover!=numTmp){
            $(".slideMenuCont .item").fadeOut(0);
            $(".slideMenuCont .item").stop().fadeOut(500); 
            $(".slideMenuCont .item").css("display","none");
            $(this).addClass("active");
             $(".slideMenuCont .item:eq("+num+")").fadeIn(500);
        }
    },
    mouseleave: function () {
        if(num<liLength)
            num++;
        myInterval();
    }
});
var Auto = function(){
    myInterval();
}
Auto();
 
}); 
Update: trying Combining both $(".slideMenuCont .item").stop().fadeOut(500); and $(".slideMenuCont .item").css("display","none");

通过存储在pair中的键查找std :: set中的键(Finding key in std::set by key stored in pair)

最满意答案

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