不安全的compareAndSwapInt与同步(Unsafe compareAndSwapInt vs synchronize)

 我会改变这一部分，如果cookie不在那里，就不要搞砸了下拉列表： 
 
$(".jTitle").each(function(){
  var $titleId = $(this).attr('id');
  var $cookieValue = $.cookies.get($titleId);
  if ($cookieValue == 'Other') {
    $(this).parent().find(".jOther").show();
    $(this).val('Other');
  } else if($cookieValue) {
    $(this).val($cookieValue);
  }                       
});
 
 唯一的变化是在结尾处添加if检查，看看是否有cookie ...如果不是下拉列表中的默认位置0（浏览器默认值）将保持不变。 

I'd change this portion, if the cookie isn't there, just don't mess with the dropdown:
 
$(".jTitle").each(function(){
  var $titleId = $(this).attr('id');
  var $cookieValue = $.cookies.get($titleId);
  if ($cookieValue == 'Other') {
    $(this).parent().find(".jOther").show();
    $(this).val('Other');
  } else if($cookieValue) {
    $(this).val($cookieValue);
  }                       
});
 
The only change is to add an if check on the end, see if there is a cookie...if not the default position of 0 in the dropdown (browser default) will be left alone.