Blackberry - 使用eclipse插件的System.out.println（）(Blackberry - System.out.println() using eclipse plugin)

 你混淆了它们的变量和字符串重复，这是一个更正的版本 
 
<li><a href="#" class="decorNavi" onclick ="xmlRequest('about')" >ABOUT</a></li>
 
 所以现在你传递一个字符串作为参数 
 
function xmlRequest(target){

        var targetClick;

        //here you say the string argument now is called targetClick
        targetClick = target;

        if (window.XMLHttpRequest) {

            xmlRequest = new XMLHttpRequest();
        }

        else{
            xmlRequest = new ActiveXObject("Microsoft.XMLHTTP");
        }

        //in this line you concatinate the variable with another string, result is a string so you dont need to quote the variable, this wouldnt work
        xmlRequest.open("GET", targetClick+".html?="+Math.random() , true);


        xmlRequest.onreadystatechange = function(){

            if (xmlRequest.readyState == 4 && xmlRequest.status ==200) {

                document.getElementById("midContainer").innerHTML = xmlRequest.responseText;
            }
        }

    xmlRequest.send();
}
 
 你需要在网络服务器上运行它，当使用“file：//”protocoll你会得到一个跨源错误，另外url需要在同一个主机上 

you mixed up variables and string represantations of them, heres a corrected version
 
<li><a href="#" class="decorNavi" onclick ="xmlRequest('about')" >ABOUT</a></li>
 
so now youre passing a string as argument
 
function xmlRequest(target){

        var targetClick;

        //here you say the string argument now is called targetClick
        targetClick = target;

        if (window.XMLHttpRequest) {

            xmlRequest = new XMLHttpRequest();
        }

        else{
            xmlRequest = new ActiveXObject("Microsoft.XMLHTTP");
        }

        //in this line you concatinate the variable with another string, result is a string so you dont need to quote the variable, this wouldnt work
        xmlRequest.open("GET", targetClick+".html?="+Math.random() , true);


        xmlRequest.onreadystatechange = function(){

            if (xmlRequest.readyState == 4 && xmlRequest.status ==200) {

                document.getElementById("midContainer").innerHTML = xmlRequest.responseText;
            }
        }

    xmlRequest.send();
}
 
you need to run this on a webserver, when using the "file://" protocoll youl get a cross origin error, additionally the url needs to be on the same host