首页 \ 问答 \ 使用bigdecimal [重复]将Java计算整除3到100(Java calculation divisible by 3 to hundred using bigdecimal [duplicate])

使用bigdecimal [重复]将Java计算整除3到100(Java calculation divisible by 3 to hundred using bigdecimal [duplicate])

这个问题在这里已有答案:

这是我的示例代码,它计算金额的百分比,在给定的例子中,我期望返回为10,但它给我9.9。 我如何将其四舍五入?

import java.math.BigDecimal;
import java.math.MathContext;
import java.math.RoundingMode;


public class Test {


    public static final int AMOUNT_SCALE = 2;
    public static final int PRECISION_SIX = 6;
    private static BigDecimal tmp = new BigDecimal("100");
    public static final BigDecimal ONE_HUNDRED = tmp.setScale(0, RoundingMode.DOWN);
    public static final MathContext MATH_CONTEXT = new MathContext(PRECISION_SIX, RoundingMode.HALF_UP);

    public  static void main(String [] args){
         System.out.println(multiplyTwoNumbersAndDivideByOneHundredAmount(new BigDecimal(30), new BigDecimal(33.33))); ;
    }

    public static BigDecimal multiplyTwoNumbersAndDivideByOneHundredAmount(BigDecimal firstNumber, BigDecimal secondNumber) {
        return (firstNumber.multiply(secondNumber)).divide(ONE_HUNDRED,MATH_CONTEXT).setScale(AMOUNT_SCALE,RoundingMode.DOWN);
    }
}

This question already has an answer here:

Here is my sample code which calculates the percentage of amounts, in the given example i am expecting the return to be 10 but its giving me 9.9. how do i round it up to 10?

import java.math.BigDecimal;
import java.math.MathContext;
import java.math.RoundingMode;


public class Test {


    public static final int AMOUNT_SCALE = 2;
    public static final int PRECISION_SIX = 6;
    private static BigDecimal tmp = new BigDecimal("100");
    public static final BigDecimal ONE_HUNDRED = tmp.setScale(0, RoundingMode.DOWN);
    public static final MathContext MATH_CONTEXT = new MathContext(PRECISION_SIX, RoundingMode.HALF_UP);

    public  static void main(String [] args){
         System.out.println(multiplyTwoNumbersAndDivideByOneHundredAmount(new BigDecimal(30), new BigDecimal(33.33))); ;
    }

    public static BigDecimal multiplyTwoNumbersAndDivideByOneHundredAmount(BigDecimal firstNumber, BigDecimal secondNumber) {
        return (firstNumber.multiply(secondNumber)).divide(ONE_HUNDRED,MATH_CONTEXT).setScale(AMOUNT_SCALE,RoundingMode.DOWN);
    }
}

原文:https://stackoverflow.com/questions/41124008
更新时间:2024-03-04 12:03

最满意答案

好的,我解决了这个问题。 问题是程序集被加载到两个域中(因为在启动程序中有一个对程序集的引用,它也被加载到默认的AppDomain,而不是加载它所要求的dll,而是继续加载来自启动器所在目录中的旧文件,因此以旧文件和启动器中包含的字节之间的清单冲突结束。 要在类似情况下解决错误,而不是在默认AppDomain中加载任何代码加载文件,请将加载移动到创建的AppDomain中。 为此,请将byte []保存到appdomain数据:

createdDomain.SetData("CommonDllAssembly", data);

然后在创建的域上运行的代码中:

byte[] bytes = AppDomain.CurrentDomain.GetData("CommonDllAssembly") as byte[];
commonDllAssembly = Assembly.Load(bytes);

这可以防止提到的错误弹出。


Ok, I got this one solved. The problem was that the assembly was loaded into both domains (since there is a reference to the assembly in the launcher, it is also loaded to the default AppDomain, which instead of loading the dll it was asked instead proceeds to load the manifest from the old file from within the directory where the launcher is, thus ending in manifest conflict between the old file and bytes contained within the launcher). To solve error in similar situations, instead of having any code loading the files within the default AppDomain, move the loading to happen inside the created AppDomain. To do this, save the byte[] to the appdomain data:

createdDomain.SetData("CommonDllAssembly", data);

And then within the code that runs on the created domain:

byte[] bytes = AppDomain.CurrentDomain.GetData("CommonDllAssembly") as byte[];
commonDllAssembly = Assembly.Load(bytes);

This prevents the mentioned error from popping up.

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