首页 \ 问答 \ 从表mysql中选择子记录(Select child records from tables mysql)

从表mysql中选择子记录(Select child records from tables mysql)

我得到了第二级儿童记录的选择声明,有更深入的问题,任何人都可以帮忙吗?

SELECT
  id_mobile AS ID_PROJETO,
  UM.qtd_UC,
  AM.qtd_AMBIENTE
FROM projetos_mobile AS PM
LEFT JOIN (
   SELECT
      COUNT(id) AS qtd_UC,
      projeto,
      data_hora_importacao,
      id_uc_mobile
   FROM ucs_mobile
   WHERE data_hora_importacao = '2015-05-15 17:21:02'
   GROUP BY projeto) AS UM
ON PM.id_mobile = UM.projeto
LEFT JOIN (
   SELECT
      COUNT(id_uc_mobile) AS qtd_AMBIENTE,
      id_uc_mobile
   FROM ucs_mobile
   LEFT JOIN (
      SELECT
         uc
      FROM ambientes_mobile AS s
      WHERE data_hora_importacao = '2015-05-15 17:21:02') AS G
   ON G.uc = ucs_mobile.id_uc_mobile
   WHERE data_hora_importacao = '2015-05-15 17:21:02') AS AM
ON UM.id_uc_mobile = AM.id_uc_mobile
WHERE PM.data_hora_importacao = '2015-05-15 17:21:02'

http://sqlfiddle.com/#!9/2eecf

如果有人想尝试一个解决方案,这里是一个sqlfiddle。 我有特定的等级:projeto> uc> ambiente> secao> medicoes

ucs_mobile.projeto refers to projetos_mobile.id_mobile
ambientes_mobile.uc refers to ucs_mobile.id_uc_mobile
secoes_iluminacao_mobile.ambiente refers to ambientes_mobile.id_ambiente_mobile

我需要为我传递的父项计算每个子项,我将有5个函数返回给定父项的每个子项的计数,例如,对于一个projeto父项我应该有计数(ucs),count(ambientes),计数(secoes),计数(medicoes)

所以,希望你们能帮助我。 数据库很难看,但这就是我得到的。 感谢任何帮助。


I got the bellow piece of select statement that got level 2 child records, having problems to got deeper, can anyone help out?

SELECT
  id_mobile AS ID_PROJETO,
  UM.qtd_UC,
  AM.qtd_AMBIENTE
FROM projetos_mobile AS PM
LEFT JOIN (
   SELECT
      COUNT(id) AS qtd_UC,
      projeto,
      data_hora_importacao,
      id_uc_mobile
   FROM ucs_mobile
   WHERE data_hora_importacao = '2015-05-15 17:21:02'
   GROUP BY projeto) AS UM
ON PM.id_mobile = UM.projeto
LEFT JOIN (
   SELECT
      COUNT(id_uc_mobile) AS qtd_AMBIENTE,
      id_uc_mobile
   FROM ucs_mobile
   LEFT JOIN (
      SELECT
         uc
      FROM ambientes_mobile AS s
      WHERE data_hora_importacao = '2015-05-15 17:21:02') AS G
   ON G.uc = ucs_mobile.id_uc_mobile
   WHERE data_hora_importacao = '2015-05-15 17:21:02') AS AM
ON UM.id_uc_mobile = AM.id_uc_mobile
WHERE PM.data_hora_importacao = '2015-05-15 17:21:02'

http://sqlfiddle.com/#!9/2eecf

here is a sqlfiddle if anyone want to try a solution. I have the specific hierarchy: projeto>uc>ambiente>secao>medicoes

ucs_mobile.projeto refers to projetos_mobile.id_mobile
ambientes_mobile.uc refers to ucs_mobile.id_uc_mobile
secoes_iluminacao_mobile.ambiente refers to ambientes_mobile.id_ambiente_mobile

I need a count of each child for the parent I pass, I will have 5 functions that return the count of each child for a given parent, for example, for a projeto parent I should have count(ucs),count(ambientes),count(secoes),count(medicoes)

So, hope you guys can help me. The database is terrible ugly but that's is what I got. Appreciate any help.


原文:https://stackoverflow.com/questions/30356797
更新时间:2023-07-21 06:07

最满意答案

实际上Boost确实有这样的适配器: boost::adaptors::reverse

#include <list>
#include <iostream>
#include <boost/range/adaptor/reversed.hpp>

int main()
{
    std::list<int> x { 2, 3, 5, 7, 11, 13, 17, 19 };
    for (auto i : boost::adaptors::reverse(x))
        std::cout << i << '\n';
    for (auto i : x)
        std::cout << i << '\n';
}

Actually Boost does have such adaptor: boost::adaptors::reverse.

#include <list>
#include <iostream>
#include <boost/range/adaptor/reversed.hpp>

int main()
{
    std::list<int> x { 2, 3, 5, 7, 11, 13, 17, 19 };
    for (auto i : boost::adaptors::reverse(x))
        std::cout << i << '\n';
    for (auto i : x)
        std::cout << i << '\n';
}

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