使用BeautifulSoup获取属性值(Getting attribute's value using BeautifulSoup)

 我正在编写一个python脚本，它将在从网页解析后提取脚本位置。 可以说有两种情况： 
 
<script type="text/javascript" src="http://example.com/something.js"></script>
 
 和 
 
<script>some JS</script>
 
 我可以从第二个场景中获得JS，也就是当JS写在标签中时。 
 
 但有没有办法，我可以从第一个场景中获得src的值（即提取脚本内的src标记的所有值，例如http://example.com/something.js ） 
 
 这是我的代码 
 
#!/usr/bin/python

import requests 
from bs4 import BeautifulSoup

r  = requests.get("http://rediff.com/")
data = r.text
soup = BeautifulSoup(data)
for n in soup.find_all('script'):
    print n 
 
 输出 ：一些JS 
 
 需要输出 ： http ： //example.com/something.js 

I'm writing a python script which will extract the script locations after parsing from a webpage. Lets say there are two scenarios : 
 
<script type="text/javascript" src="http://example.com/something.js"></script>
 
and
 
<script>some JS</script>
 
I'm able to get the JS from the second scenario, that is when the JS is written within the tags. 
 
But is there any way, I could get the value of src from the first scenario (i.e extracting all the values of src tags within script such as http://example.com/something.js)
 
Here's my code
 
#!/usr/bin/python

import requests 
from bs4 import BeautifulSoup

r  = requests.get("http://rediff.com/")
data = r.text
soup = BeautifulSoup(data)
for n in soup.find_all('script'):
    print n 
 
Output : Some JS
 
Output Needed : http://example.com/something.js

原文：https://stackoverflow.com/questions/18733023