bash：将stdout捕获到一个变量，但仍然显示在控制台中(Capture stdout to a variable but still display it in the console)

 我有一个bash脚本调用几个长时间运行的进程。 为了处理原因，我想将这些调用的输出捕获到变量中。 然而，因为这些是长时间运行的进程，我希望rsync调用的输出在控制台中实时显示，而不是事后。 
 
 为此，我找到了一种方法，但它依赖于将文本输出到/ dev / stderr。 我觉得输出到/ dev / stderr不是一个很好的做事方式。 
 
VAR1=$(for i in {1..5}; do sleep 1; echo $i; done | tee /dev/stderr)

VAR2=$(rsync -r -t --out-format='%n%L' --delete -s /path/source1/ /path/target1 | tee /dev/stderr)

VAR3=$(rsync -r -t --out-format='%n%L' --delete -s /path/source2/ /path/target2 | tee /dev/stderr)
 
 在上面的例子中，我正在调用rsync几次，我想在处理文件名时看到文件名，但最后我仍然希望输出一个变量，因为我稍后将会解析。 
 
 有没有一个“更清洁”的方式来实现这一点？ 
 
 如果它有所作为，我正在使用Ubuntu 12.04，bash 4.2.24。 

I have a bash script which calls several long-running processes. I want to capture the output of those calls into variables for processing reasons. However, because these are long running processes, I would like the output of the rsync calls to be displayed in the console in real-time and not after the fact.
 
To this end, I have found a way of doing it but it relies on outputting the text to /dev/stderr. I feel that outputting to /dev/stderr is not a good way of doing things.
 
VAR1=$(for i in {1..5}; do sleep 1; echo $i; done | tee /dev/stderr)

VAR2=$(rsync -r -t --out-format='%n%L' --delete -s /path/source1/ /path/target1 | tee /dev/stderr)

VAR3=$(rsync -r -t --out-format='%n%L' --delete -s /path/source2/ /path/target2 | tee /dev/stderr)
 
In the example above, I am calling rsync a few times and I want to see the file names as they are processed, but in the end I still want the output in a variable because I will be parsing it later.
 
Is there a 'cleaner' way of accomplishing this? 
 
If it makes a difference, I am using Ubuntu 12.04, bash 4.2.24.

原文：https://stackoverflow.com/questions/12451278